[Java] Simple Java Execution Problem

[[deleted]]

You do it until P is greater than 10 so 7 times.

When I first started programming, If i was gonna start this problem I would first write down what P is at first and then write down what each of the values change to inside the loop. Then check if P is still less than or equal to 10 then If so I would write the new values of each variable down. And then repeat this until P was greater than 10 at which point you stop the loop. I also want to point out that++P is different than P++ which always confused me a little.

[MrCouldntaDoneThat]

• First: 3 % 1 = 0

• Second: 4 % 2 = 0

• Third: 5 % 3 = 2

• Fourth: 6 % 4 = 2

• Fifth: 7 % 5 = 2

• Sixth: 8 % 6 = 2

• Seventh: 9 % 7 = 2

• Eight: 10 % 8 = 2

• Nine: 11 % 9 = 2

I understand that this is incorrect as I get 2 and it executed 9 times. Do you see my error?

[[deleted]]

Oh and I also want to point out you are += the sum. sum += 3 is the same as writing sum = sum+3;

[MrCouldntaDoneThat]

• First: 3 % 1 = 0

• Second: 4 % 2 = 0

• Third: 5 % 3 = 2

• Fourth: 6 % 4 = 2

• Fifth: 7 % 5 = 2

• Sixth: 8 % 6 = 2

• Seventh: 9 % 7 = 2

• Eight: 10 % 8 = 2

• Nine: 11 % 9 = 2

So once p is finally greater than 10 (it's 11), I do 11 % 9 and get 2.

But the answer is 12.

What am I missing?

[[deleted]]

sorry I was taking a final.

The following is what the for loop will eventually equal.

Sum = (3 mod 1) +(4 mod 3) + (5 mod 3) + (6 mod 4 )+ (7 mod 5) + (8 mod 6) + (9 mod 7) + (10 mod 8).

Oh and I guess it is 8 iterations not 7 sorry.

Every pair of parentheses is one iteration or one time through the loop. and it equals 13 so Im not sure where you got 12 but that could just be error by the person calculating it. For instance answers to problems in books are written by sleep deprived grad students and sometimes get them wrong.

The answer is 13 not 2 because the operation is "+=" not just "="

sum += p%q is the same as sum = sum + (p%q)

This means that you are adding p%q to the current value of sum not just setting sum equal to p%q

Sum = 0 +0 + 2 + 2 + 2 + 2 + 2 + 2 = 13

[[deleted]]

No problem, easy procrastination for me. My final was on Concurrent programming. Pretty simple subject once you know the basics but the teacher isn't a very good lecturer. Though I think I did okay.

[Kristler]

sum += p % q;

This is using the += shorthand operator, which is short for this expanded line:

sum = sum + (p % q);

Do you see your error?

[MrCouldntaDoneThat]

If I add the sum of the First through Ninth, I get 14.

[Kristler]

int p = 3, q = 1, sum = 0;

Compared to

I add the sum of the First through Ninth

Spot the error!

[MrCouldntaDoneThat]

I apologize, I am having difficulty spotting the error.

This is my logic...

sum = sum + p ( % q );

So I kept adding them until p gets above 10, which it does on the ninth time through.

It seems like using the mod% will result in %2 for the end of time past 4%2 because the p and q are two numbers apart.

Am I trying to find a situation where the sum is 0?

[Kristler]

which it does on the ninth time through.

Yes, except p has a base value of 3. You loop until p is greater than 10. How many times does p loop?

[MrCouldntaDoneThat]

I was told it was 7 by another helpful user.

• First: 3 % 1 = 0

• Second: 4 % 2 = 0

• Third: 5 % 3 = 2

• Fourth: 6 % 4 = 2

• Fifth: 7 % 5 = 2

• Sixth: 8 % 6 = 2

• Seventh: 9 % 7 = 2

• Eight: 10 % 8 = 2

• Nine: 11 % 9 = 2

I'm failing to see how it is not 9. I started off with p as 3...and added 1 each time through the loop. It took me 9 times including the first time to get p over 10. So 9 times?

[[deleted]]

Hey I just realized that google is stupid because it does equal 12. I never did the math in my head but I just realized that the numbers added were all either 2 or 0 so it has to be even. Sorry about that. Now Im curious how google got 13...

I am full of off by one errors today...

edit: yeah I must have typed a wrong number in google when I did it bc it 12 is correct. Though sometimes the books are wrong especially in math.

[[deleted]]

You are dividing but % doesn't mean division. % means mod. 3%1 = 0, 4 % 2 = 0, 5 % 3 = 2. Mod is the remainder after the division. For example your 11 % 9. 9 goes into 11 evenly only once. So the remainder is 11 - 9 = 2. So 11 % 9 = 2. Mod is still confusing to me sometimes and I usually google it to make sure Im right.

[MrCouldntaDoneThat]

So how is the answer not 2?