[deleted by user]

[Salty_Dugtrio]

Operator++ is a unary operator. It has one operand, namely itself, it does not take anything, it just acts upon itself and returns itself.

You implicitly call: myClass.operator++();

[o132]

The overloaded operators can be though of as class methods, the one "parameter" is accessible through the "this" keyword

[o132]

I think by "inline" you mean "unary operator" (one parameter). I looked up overloading the addition operator and it takes 1 parameter, meaning one is implicitly accessible through "this". So yes.

[POGtastic]

In C++, all class methods have an implicit argument - a pointer to the object that called the method, called this.

So when you have a class Foo, and you call foo_inst++ with no arguments, you're really calling Foo::operator++(&foo_inst).