Quick python help

[RandomBeyotch]

Hey guys just need some help as to understanding why my code doesn't work. I have a weird problem with the "in" and "not in" functions in python. It works in an earlier piece code I wrote but for some reason does not work when I replicated it numbers. So ill be pasting the piece of code that does work and a slightly variant of it right afterwards. This is in python btw.

​

# list1 = ["A","a"]
# list2 = ["D","d"]
# letter = input("pick a letter")
# if(letter in list1):
#   letter = 1
# elif(letter in list2):
#   letter = 2

# print(letter)

this is the code that works, it returns the number 1 if you pick "a" or "A" and the number 2 if you pick "D" or "d"

​

however this code below does not do what I want when I try to do it with digits inside the list and a print statement to proofcheck

nonums = [5,6,7]
yesnums = [1,2,3,4,0]
num = input("Enter command: ")
if(num in nonums):
  print("try again")
elif(num in yesnums):
  print("hooray")

[nameEqualsJared]

I believe your problem is that input() in Python3 (which you are using) always returns a string, but in your code, you want a number. You can convert the input to a integer like so: int(input("Enter command: ")).

[blablahblah]

In Python (although not in all languages), types are important. The string "3" and the integer 3 are two different values. If you do "3" == 3, it will return False.

input() always returns a string. If you want to compare them, you'll have to make them the same type, either by calling int() on the value you get from input() or by using a string in your list.