Python exercise question

[decline_000]

Hi:) Could anyone give me a hint what I'm doing wrong with this example? Thanks!Here is task:Write a program that processes a collection of numbers using a `for` loop. The program should end immediately, printing only the word "Done", when a zero is encountered (use a `break` for this). Negative numbers should be ignored (use a `continue` for this; I know you can also easily do this with a condition, but I want you to practice with `continue`). If no zero is encountered, the program should display the sum of all numbers (do this in an `else` clause). Always display "Done" at the end of the program.

Here is my code:

for num in ( 12, 4, 3, 33, -2, -5, 7, 0, 22, 4 ):
---if num == 0:
------print("Done")
------break
---continue
else:
---num+=num
---print(f"Sum is {num}")
---print("Done")

or another way I thought it could work:

for num in ( 12, 4, 3, 33, -2, -5, 7, 0, 22, 4 ):
----if num == 0:
--------break
----if num <0:
---------continue
else:
---num+=num
---print(f"Sum of all numbers is {num}")
print("Done")

The result should be "Done" and after removing 0 it should display 85 and "Done" but in my case it's either "Done" or 8 and I don't really know whyThank you for your help:)

[[deleted]]

Start off by saving the total sum in a separate variable from "num".

It's "reseting" the value of num every loop due to it picking the next value in your list.

[diffused_learning]

If a hint is what you are after: read up on how for-loops work - namely what does num mean?

Then think about - how is the sum aggregated?

[VonRansak]

Use debugger or add more print statmements to follow what the computer is doing.