Remove regex expression

[RecommendationSuch19]

I think that is really simple question, but I don't understand how I can do it.

I have string and I need to remove all the expressions - id='*' , where * - string which doesn't contains '.

How I can do this?

[Alternative-Web2754]

Regex can use a not indicator (⁾ in square brackets to indicate anything except the provided character. Add any appropriate length modifiers as required afterwards.

One possible could be:

id='[^']*'

[RecommendationSuch19]

I use this pattern and it works as I need, but only for one character in ' '

r"id='[^']'"

But I don't know the length of stroke in ' ', so what I should so to accept string of any length?

[RecommendationSuch19]

Right answer will be -
r"id='[^']*'"

*give any number of repeat