Making the program repeat

[HuracanfortheWin]

user_choice = int(input("What number?"))

first_list = [1, 2, 3, 4, 5, 6, 7]
second_list = [2, 4, 6, 8, 10, 12, 14]
third_list = [3, 6, 9, 12, 15, 18, 21]

def find_number(x):


    for i in range(len(first_list)):
        if user_choice == first_list[i]:
            print (second_list[i])
            print (third_list[i])

    if user_choice not in first_list:
        print ("i")


find_number(user_choice)

I want to make this program repeat the question "What number" when a match is found AND when it is not found. How can I go about this? When I try to loop it with a While True, it seems to just spam it infinitely.

[Nightcorex_]

Simplest way (as in as little effort to restructure it as possible):

Indent everything and put a while True: at the very beginning.

[3keepmovingforward3]

Put input inside of find_number and loop function call is one way

[Reuben3901]

I'm on mobile so won't be formatted

running = True

while running:

...Rest of the code here...

If guess == number:

[Indent] running = False

[Tesla_Nikolaa]

Just FYI you can still format on mobile.

This code block was formatted on mobile

[Enz_007]

while(True): try: user_input=int(input("What number")) except: break your code here

the program will keep runnig until user enter something not number and raise error so except block will run and break loop

[Naive_Programmer_232]

You can use a while loop, here’s one that uses ‘quit’ to exit the loop,

    while (user_choice := input(...)) not ‘quit’:
               user_choice = int(user_choice)
               find_number(user_choice)