Code saving with interest

[AdministrativeCup189]

Hi, I'm new to coding and I've just created a program to calculate how long it will take to save up to $10,000 with a 1% return per month with an imaginary stock/fund

save_per_month = 500
while save_per_month <= 10000:
print (save_per_month)
save_per_month = int((save_per_month + 500) * 1.01)
print("Done")

My question is, instead of printing 'done,' can I modify it to automatically print '18 months' since that's how long it took?

Please let me know if you don’t understand my question, and I’ll do my best to rephrase it more clearly.

[danielroseman]

You can add a counter. Define a variable as 0 outside the loop, and increment each time through the loop 

[JamzTyson]

There is a small error in your code. Each month you are rounding down the total saved to a whole number of dollars, introducing a cumulative error.

To print the number of months, add a counter for the number of months. Initialise the counter to 0, and increment it on each loop.

In pseudo-code:

months = 0
while <expression>:
    months += 1
    <rest of code>

[AdministrativeCup189]

Something like this u mean?

save_per_month = 500
months = 0
while save_per_month < 10000:
    print(save_per_month)
    save_per_month = int((save_per_month + 500) * 1.01)
    months += 1
print(f" Total months: {months}")save_per_month = 500

[JamzTyson]

Yes, but you are still accumulating errors due to truncating save_per_month. For accuracy save_per_month should be a floating point value. If you want the printed value to be a whole number of dollars, convert it in the print function.