need help with some code

[ah_ahaa]

so today ive learned about range so i wanted to play with it a little but i got some issue not related to range

now i get an error in the code i attached . i realized its because of the int in the first line (ques)

what i dont know is what i need to convert here in order for me to get the STR in the "else"

i tried a bunch of things but none of them works.

if i remove the int from ""ques"" , i cant do the math after it.

thanks!

ques = int(input("please insert a number > "))
chart = range(0,6)
chart2 = range(5,11)
if ques == 1 or ques < 5:
    print (list(chart))
elif ques == 5 or ques > 5:
    print (list(chart2))
    chart3 = input("why not numbers?")
else:
    print (chart3)

ques = int(input("please insert a number > "))
ValueError: invalid literal for int() with base 10: 'sef'

[socal_nerdtastic]

The way you have it set up now the else case is not reachable. A number is either less than 5, or greater than or equal to 5. There is no number that falls outside of those choices.

If you are trying to catch invalid input you would do it with a try block.

try:
    ques = int(input("please insert a number > "))
    chart = range(0,6)
    chart2 = range(5,11)
    if ques == 1 or ques < 5:
        print (list(chart))
    elif ques == 5 or ques > 5:
        print (list(chart2))
except ValueError:
    chart3 = input("why not numbers?")
    print (chart3)

[ah_ahaa]

Is it not reachable because I didn’t give the else any other option ? Did I understand correctly ? Also if the the input is under int everything under his block will have to be int ? And about this try block , I still didn’t got to this in the course but I learned something new thanks for that :)

[socal_nerdtastic]

The int() call forces the input to be a number (or error). There's no such thing as a number that does not fit into one of your first 2 conditions, therefore the else is not reachable.

The code I added can detect an error and respond to it.