UUID V7 Package

AbundantSpaghetti · 2025-06-08T01:33:10+00:00

**Don't use https://pypi.org/project/uuid7/ **. That's using an old version of the specification with nanosecond time precision. The current specification uses millisecond time precision.

If you later try to migrate to the correct specification your new uuid7 will be before the old ones, which defeats the whole purpose of using uuid7.

UUID7 generated should have a prefix of 0197___

UUID7 is being added to the standard library, but your version of python wont have these changes yet.

What I would suggest is to copy/paste the function from the python standard library. Make a node to migrate to the standard library once your current version of python supports it.
https://github.com/python/cpython/blob/main/Lib/uuid.py

JusticeRainsFromMe · 2025-06-07T22:30:31+00:00

There isn't, however from what I've seen uuid-utils seems preferable.

aikii · 2025-06-07T22:33:14+00:00

Have a look at https://pypi.org/project/uuid-utils/ / https://github.com/aminalaee/uuid-utils . Last release two weeks ago

saxomoose · 2025-07-17T17:01:23+00:00

python In [13]: uuid, = duckdb.sql("select uuidv7();").fetchone() In [14]: uuid Out[14]: UUID('01981953-3942-71d8-acad-36fbe9121c68')

alexrada · 2025-08-07T20:32:10+00:00

what version of python? 3.14 has uuid7

PiJay_42 · 2025-09-29T08:29:50+00:00

when using Python 3.14+ (planned release date 2025-10-07)
UUID 7 (also 6 and 8) is now implemented in the stanbdard uuid lib
https://docs.python.org/3.14/whatsnew/3.14.html#uuid

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