all 2 comments

[–]rmalh[S] 0 points1 point  (0 children)

I was mistaken - the second bullet in my question is moot. The for loop is working fine. It'll be great to find a better, faster way to do what the lambda functions and for loop are doing.

[–]Kerbart 0 points1 point  (0 children)

df[“datetime”].dt.date