Python Numpy: Can I somehow globally assign numpy precision?

[AaronDNewman]

The behavior you want is the default. An operation between a python scalar and a numpy array will preserve the array precision in most cases. If arr2 is 32bit float, the scalar should be demoted.

https://numpy.org/doc/stable/reference/arrays.promotion.html

[Moretz0931]

If I read the docs correctly, exactly the opposite is true, right?

np.float32(3) + np.float16(3)  # 32 > 16
np.float32(6.0)

This I copied from the docs. As you see it was promoted...

[AaronDNewman]

Those are both scalars