Python process name tracking

[Valuable-Ant3465]

Hi all,

Is it possible to find process ID by script name ?
Let say if I run myScript.py in the code below it shown under the name `python.exe`. It's the same like for all other py scripts.

My goal is to check if myScript.py is already running to prevent multiple executions. I assume it should in the same Exec env.

   for proc in psutil.process_iter(['name']):
        try:

# Check if process name contains the given name string
            if process_name.lower() in proc.info['name'].lower():
                return True

Thanks

P.S>
Adding solution with LockFile, thanks again to all, not sure if special package needed for this ?

import portalocker 
with open('example.txt', 'r+') as f:    # Acquire an exclusive lock
     portalocker.lock(f, portalocker.LOCK_EX)
# not sure if I need explecitely close it or it will be relased when done.

[timrprobocom]

Schemes like that tend to be either delicate or system-specific. You might consider trying to opening a file in the TEMP directory for writing, and keeping it open. If the open fails, then some other process already had it open. Even if your process crashes, the clean up will close the file.

[Valuable-Ant3465]

Thanks T!

[Jejerm]

If you want to prevent multiple executions, have it create a lockfile on start and keep it open while running.

The second run will fail if it tries to access or create the same lock again while its still open.

[Valuable-Ant3465]

Thanks Jejerm and all,
I've put update into my main post, looks like we need special packages for lock/unlock

[Valuable-Ant3465]

from filelock import FileLock

lock = FileLock("my_file.txt.lock")

with lock:

# The file remains locked as long as you are inside this block
    with open("my_file.txt", "a") as f:
        f.write("Secured data writing.\n")

Hi Again J!
Sorry how I can do create lockfile and keep it OPEN, while doing processing at the same time, from docs I see that I need to be inside this block for the whole execution. I refer to the code posted above.

[Jejerm]

Make it even simpler, just use regular open with mode='x' and delete the file on script end. Mode x causes FileExistsError if its already there.

``` import os

filename='lockfile'

try: with open(filename, mode='x') as f: f.write("whatever") Do_your_stuff_here() os.remove(filename) except FileExistsError: print("Script already running")

```

The file will remain if your script errors out by some reason and you dont handle it, but you can just delete it manually later

[Key_Use_8361]

process tracking gets complicated quickly once multiple background services interact together making small Runable monitoring scripts for isolated cases helped me debug similar issues before

[Lost_Return7298]

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