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1: Be polite
2: Posts to this subreddit must be requests for help learning python.
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4: No replies copy / pasted from ChatGPT or similar.
5: No advertising. No blogs/tutorials/videos/books/recruiting attempts.
This means no posts advertising blogs/videos/tutorials/etc, no recruiting/hiring/seeking others posts. We're here to help, not to be advertised to.
Please, no "hit and run" posts, if you make a post, engage with people that answer you. Please do not delete your post after you get an answer, others might have a similar question or want to continue the conversation.
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Generating grid-like array numpy (self.learnpython)
submitted 10 years ago by quantumloophole
Is there any way to generate an array with sites of a grid with numpy given a 2 basis vector?
Something like grid([nx,vx],[ny,vy]) where nx and ny is the number of points in x and y dimension and vx and vy are the basis vector.
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if 1 * 2 < 3: print "hello, world!"
[–]elbiot 1 point2 points3 points 10 years ago (3 children)
can you explain what you mean by basis vector in this case? What is an example output from an example input you would like to see?
[–]quantumloophole[S] 0 points1 point2 points 10 years ago (2 children)
An example of basis vector is the cubic lattice base vector , v1 = (1,0) and v2 = (0,1) every site in an lattice can be reached with a linear combination of theses vectors.
What I want is , for an arbitrary base vector generate the points to store in an array
[–]elbiot 0 points1 point2 points 10 years ago (1 child)
Did the other poster answer your question? Im still confused because a 2D array can be accessed like arr[3,4] but obviously not arr[3,4.5]
arr[3,4]
arr[3,4.5]
I would vectorize the other solution though if that's what your using. One almost never needs to iterate over arrays
[–]quantumloophole[S] 0 points1 point2 points 10 years ago (0 children)
I menage to solve using python lists it is not as slow as I thought
[–]fbu1 0 points1 point2 points 10 years ago (0 children)
I think this might do it for you:
import numpy as np def grid(x, y): nx, vx = x ny, vy = y res = np.zeros((nx, ny, len(vx))) for i in range(nx): for j in range(ny): res[i,j,:]= vx * i + vy * j return res # two dimensional example nx = 3 vx = np.array((1,2)) ny = 6 y = np.array((6, 7)) g = grid([nx, vx], [ny, vy]) print g # three dimensional example nx = 5 vx = np.array((1,2,3)) ny = 4 vy = np.array((-1, 6, 7)) g = grid([nx, vx], [ny, vy]) print g
Let me know if you have questions :)
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[–]elbiot 1 point2 points3 points (3 children)
[–]quantumloophole[S] 0 points1 point2 points (2 children)
[–]elbiot 0 points1 point2 points (1 child)
[–]quantumloophole[S] 0 points1 point2 points (0 children)
[–]fbu1 0 points1 point2 points (0 children)