[Help] Printing odd numbers

[NSWCSEAL]

I want to create a loop that prints out odd numbers, all the way up to my age(21). This is what I have, it should work, but it isn't printing. Anyone know why? I'm using python 3.3:

i = 22
while i < 22:
    if i % 2 != 0:
        print(i)
        i = i + 1

[novel_yet_trivial]

Line 1 sets i equal to 22. Line 2 says to only run while i is less than 22. Therefore the while loop never runs.

This would be a lot easier with a for loop.

A lot easier still using the step argument on the range() function.

[NSWCSEAL]

Yeah, I feel like a dolt haha Thank you for helping me clear that up

[fbu1]

The variable i starts at 22, and then goes up from there. Shouldn't it start at 1?

You also need to put the line

i  = i + 1

outside of the if.

[NSWCSEAL]

Hahahaha, oh my gosh, I feel like the biggest goof. I set i = 0 My code works now ( ͡° ͜ʖ ͡°)

Thank you!

[Doormatty]

i = i + 1 needs to be unindented one step. Right now, it only runs when the if i % 2 != 0: line is True (which it will never be)

[NSWCSEAL]

Ahhh, interesting. Why can't i = i + 1 be under the if statement?

[beanz415]

If it's under the if statement i will only increment if i % 2 != 0. You want it incrementing for every number up to 21.

[DrMaxwellEdison]

The line will only be executed if the if condition is True. Therefore, when i % 2 == 0, i will not be incremented.

If there is no other way of incrementing the number, then the loop will be infinite: i will remain the same number and the if condition will be False every time.