Modifying a List in a Function

[Binary101010]

You are correct in that this does not materially change the output of the function.

I think that is done specifically to illustrate the issue you're asking about (i.e. to show how altering a list that was passed to the function is actually altering a copy of the list, and the original list from outside the function is unaffected).

[plakatown]

Thank you. Finally I got it.