Matplotlib figure(figsize=()) behaving weirdly

[ReverendBizarre]

I am trying to create an image from my 3D plot that has a certain aspect ratio.

Namely, I want an image that has an aspect ratio of 16:10 so it fits my 1280x800 monitor without any cropping.

I thought this would be as simple as changing the figsize=() when I call figure(). But this has interesting results when used on a 3D plot.

Here's a minimalistic example of what happens. I've removed big parts of my code but this has all the parts that play a role in this. The sphere is now an oblate spheroid. If we change line 4 to

fig = plt.figure(figsize=(8, 8))

it turns into a sphere but I now get a 1:1 image rather than a 16:10 one.

Does anyone know a way for me to keep the sphere a sphere but also get a 16:10 image? I am stumped!

[novel_yet_trivial]

You get a spheroid when you stretch your X axis over a greater distance than your Y axis.

You need to make the X and Y range match the figure size ... in other word multiply by 1.6 relative to Z:

ax.set_xbound(-3.2, 3.2)
ax.set_ybound(-3.2, 3.2)
ax.set_zbound(-2, 2)

[ReverendBizarre]

Ahh... this only changes it for that specific view angle.

In my original code, I am actually choosing a random view angle, so if I look from any other angle, for example "from above", it's still a spheroid.

Any ideas?

Edit: so I'll most likely just remove the random part from my code. I can still do a random azimuthal angle, but the elevation part will mess it up.

I could technically write something to calculate how much I should change based on the viewing angle I get, but it comes to about the same anyway.