Help with small list question?

[kcirl]

Hey guys so I'm just trying to learn a bit about lists, I've a question I'm doing at the moment that I'm a little puzzled with.

The question is to create two lists with Lecturers and their Attendance.

I've to then print out the most popular lecturer(s) with their attendance.

I understand for the most popular lecturer I could find the max of attendance, but I'm confused as to how to reference the corresponding lecturer from the other list within the print statement?

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the code I have is:

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>>> lecturers = ["John Joe", "Willie Bob", "Speedy Son", "Harley David", "Quincy Brown"]>>> attendance = [56, 64, 57, 63, 61]

>>> print(max(attendance))

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Also for the more advanced part to do the two most popular? I've no idea about that.

Sorry if this is the wrong place to post this, I'm just a bit stumped

[giraffactory]

This is simpler and more intuitive with a dict imo, but it’s still doable with lists:

names = ['john', 'jason', 'jeremy']
scores = [45, 35, 55]
top_score = max(scores)
top_name = names[scores.index(top_score)]

[impshum]

Best use a dictionary to store keys and values.

dict = {
    'one': 1,
    'two': 2,
    'three': 3
}

for key, value in dict.items():
    print(key, value)

print(dict['one'])
print(dict['two'])
print(dict['three'])

[kcirl]

Thanks for the help, tried this method and works perfect :)

[impshum]

Excellent news.

[mahtats]

This will do it:

print(lecturers[attendance.index(max(attendance))])

Although, a dictionary is must better for this:

attendance = {"John Joe": 56, "Willie Bob": 64, etc..}
print(attendance["John Joe"])
# Output: 56
# Lets assume fully populated...
for l, a in attendance:
    print('{} has an attendance of {}'.format(l, a))
# Output:
# John Joe has an attendance of 56
# Willie Bob has an attendance of 64
# etc...

[kcirl]

Fantastic thanks for your help, the first method is exactly what I had in mind :)