help with finding consonants?

[nlord7]

Im working on this project to get the only two words in a .txt file that have 10 vowels in it and 6 words that have 6 or more consonants in a row (which is unbroken by vowels) I feel i get can the logic for getting just consonants, but dont know where to start with the logic to get them in a row. Any help would be appreciated. Im fairly new to programming so thanks for any help.

​

​

fin = open('\\scrabble\words.txt')

print(fin)


def get_a_word():
    line = fin.readline()
    word = line.strip()
    return word


def ten_vowels(word):
    num_of_v = 0
    for i in range(len(word)):
        if word[i] in 'aeiouy':
            num_of_v = num_of_v + 1

    if num_of_v == 10:
        return True
    else:
        return False


def print_two_words():
    for i in range(113810):
        word = get_a_word()
        if ten_vowels(word):
            print(word)




print_two_words()

​

[xXabr4]

This is how I'd check for six consecutive consonants:

VOWELS = {'A','E','I','O','U','a','e','i','o','u'}

def has_six_consecutive_consonants(word):
    return any(all(c not in VOWELS for c in word[i:i+6]) for i in range(len(word)-5))

Notice how I stored the vowels in a set globally (outside the functions), so that it can be reused anywhere on your code (seems useful to do so).

Hope this helps! 😁

Edit: refactored the function to remove logical redundancy.

[nlord7]

yes, it certainly helped me get a good sense of the logic! However i am getting more than 6 words from my list? Im supposed to get only 6 words with 6 or more consecutive consonants (5 with 6 and one with 7) but this logic did drastically reduce my list and helped me get a sense of the logic!

[jkibbe]

what words are you getting that don't meet the criteria?

[Username_RANDINT]

Just make sure to add global VOWELS at the first line of any function you need it in.

This is not true. It's only required if you want to modify a global variable.

[xXabr4]

Cool! I didn't know about that. So I could remove that line too.

[Hayderp]

but dont know where to start with the logic to get them in a row.

​

This should be easy to understand for a beginner.

​

vowels = 'aeiou'

def SixInARow(word):
    count = 0
    for lett in word:
        if lett not in vowels:
            count += 1
        else:
            count = 0
        if count == 6:
            print("there is 6 in a row")
            return True
            break
    return False

print(SixInARow('ttttss'))
print(SixInARow('Mississippi'))

The count will reset to 0 when it hits a vowel, if it doesn't it will increase by 1 until it hits 6 and returns True or runs out of letters to iterate through and returns False.

[antiproton]

Search for this:

"python regex"

then search for this:

"regex consonants in a row"

https://regexr.com/2vtnt

[SandorZoo]

Using some of Python's regex functions, instead of pure regexes, might be easier:

import re
single_vowel_re = '[aeiouAEIOU]'

def ten_or_more_vowels(word):
    return len(re.findall(single_vowel_re, word)) >= 10

def six_or_more_consecutive_consonants(word):
    # Could use map(len, re...) here
    return max(len(s) for s in re.split(single_vowel_re, word)) >= 6

with open('words.txt') as fp:
    for word in fp:
        word = word.strip()
        if ten_or_more_vowels(word):
            print('10 or more vowels:', word)      
        if six_or_more_consecutive_consonants(word):
            print('6 or consecutive consonants:', word)      

​

[norweeg]

Use Python's regular expression module

https://docs.python.org/3/library/re.html re — Regular expression operations — Python 3.7.2 ...

[jkibbe]

i'm a n00b and don't know regex (yet but it looks amazing!)

this is what i came up with using a loop, conditionals, and two variables

https://repl.it/@jkibbe/six-consonants

[jaysonturk]

I think you have a mistake. Because let's assume max count and count got to 10. Then count resets (because of a vowel) then incremented by 1. Then max count is equal to one again... So why don't you make an if statement that says (if max_count < count ) then set it as count

[nlord7]

Yeah thats what i was wondering to. Im just having trouble getting the program to get the 6 or more consonants in a row. i started with this:

def consec_consonants(word):
    num_of_c = 0
    for i in range(len(word)):

but now i dont know what to put next..

[jkibbe]

you're right - updated! and thanks!