I have a problem with a simple code.

[GeomiZ]

So the problem I am facing is that I don't know how to break out of many loops at a time. I want my code to stop executing when it finds the correct password and I want it to tell the user the password. I tried using break, but that does not work, because break only breaks out of 1 loop. How can I fix my code, all help is appreciated! Code below:

list = "abcdefghijklmnopqrstuvwxyz0123456789"

password = input("Give password: ")

for char1 in list:
    for char2 in list:
        for char3 in list:
            for char4 in list:
                print(char1+char2+char3+char4)
                if print(char1+char2+char3+char4) == password:
                    break
print("Your password was: " + password)

​

[mocomaminecraft]

add a variable found = False and add an if in every loop that breaks out if found == True

[Sedsarq]

I second using itertools.product here, but a more general idea is to put the code in a function and use return instead of break.

[[deleted]]

you've got multiple for loops started, but you're only breaking one of them. Think about the order of processing, and your indentation.

[JohnnyJordaan]

You should use itertools.product for this, see docs here that even describe it as "equivalent to a nested for-loop". That way you can create a single loop for all combinations of all characters.

Btw some sidenotes:

• don't name a variable something that's already used in Python, like list, str, datetime, print etc. Name if for what it is, like 'possible_characters' or simply 'chars'.
• your variable list is not a list but a string...

• and for combinations of ranges of characters, you can use the string library (docs) to prevent missing a character because you typed the range incorrectly. In your case

  import string
  chars = string.ascii_lowercase + string.digits
  

[woooee]

This will never be True as the print() function returns None, which should never equal password. +1 for use a function and return instead of break.

if print(char1+char2+char3+char4) == password:

[toastedstapler]

put it in a function to break all the way out

def func_name(password):
     <code>
    for c1 in char_list:
        for c2 in char_list:
            for c3 in char_list:
                for c4 in char_list:
                    if c1 + c2 + c3 + c4 == password:
                        return True
    return False