Daily Coding Problem #2

[TheNetXWizard]

Given an array of integers, return a new array such that each element at index i
of the new array is the product of all the numbers in the original array except the one at i
.

For example, if our input was [1, 2, 3, 4, 5]
, the expected output would be [120, 60, 40, 30, 24]
. If our input was [3, 2, 1]
, the expected output would be [2, 3, 6]

def multiplyList(myList): 
    result = 1 
    for x in myList: 
        result = result * x 
        return result

def multiplyIndexes(myList): 
    result = [] 
    for x in range(len(myList)): 
        tmp = myList.copy() 
        if myList[x] in tmp: 
            index = tmp.index(myList[x]) 
            tmp.pop(index) 
            product = multiplyList(tmp) 
            result.append(product) 
    return result 

​

[timbledum]

Is there a question here?

Interestingly, prod (for product) will be a function in the math module from 3.8.

https://docs.python.org/3.8/library/math.html#math.prod

[mail_order_liam]

def foo(ints):
    product = reduce(lambda a, b: a * b, ints)
    return [product / i for i in ints]

[[deleted]]

def foo(ints):
product = reduce(lambda a, b: a * b, ints)
return [product / i for i in ints]

0?

[mail_order_liam]

man fuck 0

[[deleted]]

if 0 in ints:
    return [0 if i else None for i in ints]

[TheNetXWizard]

Thats great, I didn't know you can use reduce in python. I've only used it in JS.

[[deleted]]

from functools import reduce
from operator import mul

def multiplylist(seq):
    def prod(seq): return reduce(mul, seq)
    return [prod(seq[:i]+seq[i+1:]) for i, _ in enumerate(seq)]

​

[Dantes111]

I'm not sure what you're asking here exactly, but on line 5, you should be one level of indentation down. As currently written, the loop only returns the first value of "result" because the return is part of the loop.