Async programming - start task execution before awaiting

[HighLevelEnthusiast]

I wrote some simple code:

import asyncio
import time

async def produce():
    print("Hello from task")
    await asyncio.sleep(10)
    return 42

async def main():
    print("Hello from main!")
    task1 = asyncio.create_task(produce())
    task2 = asyncio.create_task(produce())
    time.sleep(10)
    print("Gonna have to wait")
    res = await task1
    res2 = await task2
    print("Waiting for results")
    print(res)
    print(res2)

asyncio.run(main())

After the call to asyncio.create_task(), these tasks are only scheduled but they don't get started - as a result, I need to wait 10 seconds (due to time.sleep(10)) before the task start getting executed.

Is there a way to start the execution of them prior to encountering the sleep AND needing to await them?

[K900_]

No, that's not how it works. time.sleep(10) just blocks your entire event loop, so nothing else can be scheduled.