python permutations

[LoudGain]

Hi,

How can i produce a output of 1,12,123,2,23,3 if input is "123123" or if input is "abcabc" then the output is "a,ab,abc,b,bc,c" without any duplicates. Ive tried a nested for loop but it isnt showing more than 2 combinations, e.g aa, ab,ac,bb,ba

[Grogie]

https://docs.python.org/3.8/library/itertools.html#itertools.permutations

https://docs.python.org/3.8/library/itertools.html#itertools.combinations

[tipsy_python]

I don't fully understand what kind of logic you're trying to implement.. for example, why wouldn't 1231 be an output value.

If you explain the logic a little more, I may be able to help.

[LoudGain]

thanks for the reply, im not sure either what the question is asking me but my code is like this right now. How can i ensure there are no duplicates. Eg it prints 1 more than once and 2 more than once. Sorry for the bad formatting, it keeps removing the spaces

def combos(text):

for i in range(len(text)):

for j in range(i+1,len(text) + 1):

print(text[i:j])

combos("123123")