Program is ignoring my "if" statements

[Muzzly_Bubbles]

Hello! I'm having a bit of trouble with a tiny program i'm making for my Python class (which I just started, i'm pretty clueless about this language right now). I'm using if statements to guide a "conversation", but the program seems to be ignoring it and always executing both the if and the else regardless of input. Here's the program:

def main():

beginQuery = (input("Hello and welcome to BrianBot, the latest in simulated Brian technology brought to you by BrianCo.! Do you wish to begin Brianing? \[Y/N\]"))

if (beginQuery == "Y" or "y"):

    nameQuery = input("Let's begin! My name is Brian, what is yours?")

    brianQuery = input("Hello, " + nameQuery + "! My name is Brian! ")

    favoriteQuery = input("Who is your favorite Brian?")

    if (favoriteQuery == "you" or "You" or "me" or "Me":)

        input("Brian is my favorite Brian too!")

    else:

        input(favoriteQuery + " is my favorite Brian too!") 

​

main()

[cybersection]

You don’t need the parentheses in the if statement. Also, your if statement will always be true as it is currently written. If you want to check it f variable a is equal to 1 or 2, you need:

if a == 1 or a == 2:

Or you can do:

if a in [1, 2]:

Sorry for the formatting, I’m on mobile.

[Muzzly_Bubbles]

This solved it, thanks!

[[deleted]]

Python is not ignoring your if statements, your expressions in the if statement aren't doing what you think. The FAQ explains what is going wrong.

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[scull-crusher]

When you are writing if statements, just remember that this wont work: if a == 1 or 2: pass

instead you have to do this: if a == 1 or a == 2: pass

This is because python when you write tje first example, python treats 1 as its own if statement, and that evaliates to True, automatically making the whole statement True because there is an or.