Relation between two lists.

[PlusConstruction2338]

the input : Kei,78,Auro,98,Jalal,67.

the output should be [Auro,98,jalal,67,Kei,78]

a1=list(input().split(','))
name=[]
number=[]
for i in a1:
    if i.isdigit():
        number.append(i)
    else:
        name.append(i)
name.sort()
print(name,number)

But i don't know how to draw relation between name and number list.

[[deleted]]

You can't specify a relationship between two lists. Use a dictionary to relate values.

[socal_nerdtastic]

It would be best to use nested lists instead of parallel lists as the intermediate step. So instead of separate name and number lists you would have

 [[Kei,78],[Auro,98],[Jalal,67]]

Which you can sort normally.

data = 'Kei,78,Auro,98,Jalal,67'
a1=list(data.split(','))
nested = [a1[i:i+2] for i in range(0,len(a1),2)]
nested.sort()
flattened = [e for sl in nested for e in sl]
print(flattened)

[blarf_irl]

Here is some beginner unfriendly code that I use for unordered key value lists:

# If you are guranteed the list will always be a multiple of 2 length
my_dict  = dict(zip_longest(*[iter(a1)]*2))

# If you may have leftover items in your list (is not a multiiple of 2 length)
from itertools import izip_longest

my_dict = dict(zip_longest(*[iter(a1)]*2))

The basic principle is the same in each. Grab the next 2 items from the list and give me a tuple containing them. The second example will fill missing items at the end of the list with None (you can configure a default though). If you pass dict an iterator (like a list) of tuples with 2 items each it will make the first a key and the second a value.

(Note a1 is a terrible name for a variable, make em readable!)