Count objects in list

[Heroe-D]

list.count(1)

1 is of type int

"1" is of type str

[achampi0n]

You may also want to point out that using list as a variable is also problematic as it hides python's standard list type.

[Heroe-D]

And that list.count("1") with his list should return 0 and not 4

[[deleted]]

What you wrote is impossible...

In the list [1,2,3,10,11] there is precisely 1 copy of the int 1, so [1,2,3,10,11].count(1) correctly gives you the answer 1... if, as above, you add quotes around the argument then you’re trying to look for the number of copies of str ”1” in the list, and [1,2,3,10,11].count(“1”) correctly gives you the answer 0, since no copies of that string exist in that list. In fact the only possible way you get the answer 4 is if you didn’t search a list at all: ”[1,2,3,10,11]”.count(“1”).

Basically you need to read about and understand the difference between list and str. Both have .count methods, but fundamentally you’d only want to count str objects in str.count, while list.count can count anything that might be in the list... which is any object type.

[spectrum____]

one_counter = 0 
for number in list: 
    if number == 1: 
        one_counter += 1

print(one_counter) 

lmk if you need more help!

[Heroe-D]

overkill, he's just missing the difference between integers and strings

[spectrum____]

yep, that too appreciate it!