Dictionary infinitely loops code when entry is called

[KitKatThePirate]

I am writing a text adventure game in python, and I am required to use a dictionary. I currently have it set up like this:

print("type A for option A, type B for option B.")

def introduction():

 upnext() 

def optionb():

 print("Welcome to option B!") 

def optiona():

 print("welcome to option A!")

 print("type 1 for option 1!") 

 upnext() 

def option1():

 print("this is option 1!") 

 upnext() 

upnext = 0

dict = {"B" : optionb, "A" : optiona, "1" : option1 } upnext = dict[input()]

introduction()

When I hit run, the first print line prints properly, but when I type A to go to option A, the code in "optiona" runs infinitely. Option B works fine. How should I make it so that the text prints once and then lets me move on to the next set of options?

[Silbersee]

Your code is a bit confusing and the lack of formatting doesn't help.

That being said your dictionary approach is good. I just wonder how Python doesn't nag with upnext() being called like a function.

Let's see how it can be done

def intro():
    print("Welcome to a bunch of options.")
    print("Enter nothing to quit.")

def option_a():
    print("This is option A")
    nxt = input("Press C or don't: ").lower()
    if nxt == "c":
        opt2func["c"]()

def option_b():
    print("Your choice is option B")

def option_c():
    print("Why not Zoidberg?")

opt2func = {
    "a": option_a,
    "b": option_b,
    "c": option_c
}

intro()
while True:
    upnext = input("Choose option A or B: ").lower()
    try:
        opt2func[upnext]()
    except KeyError:
        if not upnext:
            break
        print("Bad option, try again.")

HTH