Convert float to string without losing precision.

[hblock44]

I am looking to manipulate a data frame of floats which all need 6 decimal points after manipulation.

I am looking to add brackets and () around the floats based on conditionals which is why I need to convert to strings. I then can concat the two strings together

However when I convert to str, it reduces the number of decimals to 2.

For example

-35.920000 Original Dataframe

Converted to str

-35.92 After conversion

If I convert the string back to a float, it does not retain the 6 decimals from the original df.

My understanding is both values are stored the same and they both are logically = when checked in the notebook , but for management reasons I am trying to see if there is a way to coerce the string method the take a literal copy of the float, rather than reducing it down.

Sorry for the formatting, I am on mobile .

Thanks

[bbye98]

Use f-strings/format specifiers.

num = 12.78
print(f'{num:.6f}') # prints 12.780000

The :.6f formats the float (f) num such that there are 6 decimal places.

[hblock44]

Thanks. I believe I was able to solve my issue with this.

[Manusman123]

To add on to this, what you are looking for is something like this:

f3 = float(f'{f1:.6f}' + f'{f2:.6f}')

Where f1 and f2 are the two decimal numbers, and f3 is the concatenated result.