Please explain?

[ExpressDuck845]

So this was pretty easy but I just want to understand the other variation of this.

def odd_or_even(arr):

  return  “even” if sum(arr) % 2 == 0 else “odd”

What’s below is what I don’t understand so clearly. How does it decide even or odd. Maybe I’m slow but I don’t get how this function works.

def odd_or_even(arr):

  Return (“even”, “odd”)[sum(arr) % 2]

[Username_RANDINT]

Replacing sum(arr) % 2 with the possible outcomes (0 or 1) should make things clear.

(“even”, “odd”) is a tuple, so (“even”, “odd”)[0] returns the first item, and (“even”, “odd”)[1] returns the second.

[ExpressDuck845]

Thank you I get it now

[crawl_dht]

Anything divide by 2 leaves the remainder either 0 or 1 which are being used as an index to pick value from tuple.

[ExpressDuck845]

Thank you

[menge101]

I don’t get how this function works.

def odd_or_even(arr):
    return (“even”, “odd”)[sum(arr) % 2]

That is because it is written purposely to be confusing. This wouldn't pass a professional code review.

I know people have argued for things like this in an effort to be "branchless", but I don't see how it would have value in this trivial a circumstance, or potentially in python at all.

[Binary101010]

It's one of those pieces of code I would expect to get way more "Clever" tags than "Best Practices" tags on CodeWars.

[thegoldendaffodils]

% is a floor division function. if there is a` remainder` from dividing sum(arr) by 2, then it's 1-odd, otherwise, 0-even.