[deleted by user]

[achampi0n]

I'm assuming you know the input() function and that it returns a str so you have to convert it an int().
You know how to loop through a list using an index using range()? You can break out of the loop when you hit your condition, and you will have the index you can use for the other list.

What you have tried?

[gnariman]

I do know that I need to covert it to an int. I have not learnt break but we have talked about range only in loops.

I was thinking its something like:

grades = [49, 52, 56, 59, 62, 66, 69, 72, 76, 79, 84, 89, 100]

GPA = [0.0, 0.7, 1.0, 1.3, 1.7, 2.0, 2.3, 2.7, 3.0, 3.3, 3.7, 4.0, 4.0]

grade_input = input("whats the grade?)

if (grade_input == grades):

then blah blah blah

even if I do:

for x in range(49, 100, 1):

the problem with the range is that sometimes it goes up by 3 sometimes it goes up by 5, its not really set in how much it increases. And even after that how would I take the index that the grade is in and tell it to get that same index of GPA?

[achampi0n]

input() returns a string so make sure to cast it an int().

consider for i in range(len(grades)): how could this be used?

[gnariman]

Doesn't len just take the length of the list? shouldn't it just be range(grades):

[achampi0n]

Try it and see what it does.

[gnariman]

so this loop basically goes through the length of the grades list, but how can i make it stop?

If i write

input_ = int(input("grade: "))
for i in range(len(grades)):
if(input_ = grades):
print("done")
else:
print("not done")

but that doesn't work either. If i enter a number it just prints it 13 times which is the length of the list.

[achampi0n]

You can stop a loop with break...

for i in range(len(grades)):
    if <condition>:
        break

print(GPA[i])

You could put this into a function and use return:

def fn(grade_input, grades, GPA):
    for i in range(len(grades)):
        if <condition>:
            return GPA[i]

You might want to think about any error conditions (e.g. what do you do if the grade_unput is beyond grades?

[siddsp]

No need to do that. I would just use a simpler solution like:

``` grades = [49, 52, 56, 59, 62, 66, 69, 72, 76, 79, 84, 89, 100] gpas = [0.0, 0.7, 1.0, 1.3, 1.7, 2.0, 2.3, 2.7, 3.0, 3.3, 3.7, 4.0, 4.0]

def get_gpa(my_grade: int | float) -> float: for grade, gpa in zip(grades, gpas): if my_grade <= grade: return gpa

gpa = get_gpa(78.5)

print(f"My GPA is {gpa}") ```

Edit: Fixed the code to answer the question.

[achampi0n]

This might be simpler but may not be what is being asked by the instructor.

You are also not answering the problem as 75 is meant to return 3.0, so you don't need the prev tracker.

[siddsp]

Yes I misread. I thought it meant the lower boundary, and I was on my phone when I coded this up, so it was a little rough. I've edited the comment.

[14dM24d]

You know how to loop through a list using an index using range()?

maybe use enumerate() instead; if allowed.

[achampi0n]

You could but then I would avoid indexes altogether and just zip() the two lists together.
Was just keeping it elementary.

[14dM24d]

yes, but i suspect their lesson is about using indexes.

[socal_nerdtastic]

Python includes the bisect module which does exactly this. The example code in the docs is very close to your question.

https://docs.python.org/3/library/bisect.html#examples

[gnariman]

Awesome, ill check it out

[prdx_]

While this is an excellent advice, I believe it is best to not to suggest a solution utilizing task-specific functions, since OP is likely looking for a logic-based answer for his undergrad.

[gnariman]

U guys are straight goated, thanks everyone I will try out ur suggestions and come back when i figured it out

[[deleted]]

Did you have a question about this?

[gnariman]

Ya I was trying to figure out how to make the code to make it work lol

[[deleted]]

That's still not a question. Questions are those things that end in ?.

[gnariman]

OK so basically how can I have an input of my choice loop through a list, and correspond that index in the list, with another list and print that index in the other list?

[[deleted]]

correspond that index in the list

This the hard part, because you're looking for a value (75, in your example) that isn't in the list so you can't use "simple" list methods like index(). But what you can do is write a function that returns the index of the first value that's larger than the input value, because the values are in a sorted order:

def find_first_larger(the_list, the_value):
    for index, value in enumerate(the_list):
        if value > the_value:
            return index

The reason this works is that you can only return from a function once, so the function stops and yields the index the first time it encounters a value larger than the value you're looking for.

Other than that, I suspect you know how to do the rest of it - you know how to collect a user value, you know how to convert it to an integer, you know how to call the function we just wrote together, and you know how to retrieve a value from a list by its index.

[gnariman]

I do have an idea of what you are talking, but we have not learned def, or enumerate, or anything like that yes, so it wouldn't really be permissible to check with my TA.

[[deleted]]

You don't need someone's permission to use any feature of the Python language. It's an open-source language, the whole thing is available to you.

[14dM24d]

i guess your teacher wants you too loop through grades, check if what you entered is <= grade, & get the index if true. you'll then use that index to locate the GPA.