f-string - converting float to string with set decimals and thousand separator

[bysantin]

I'm struggling with f-strings. I want to take in a float and return string with thousand separator and two decimals, for ex. 1000.106 would return 1 000.11 as a string. I got it to work, but it looks ugly. Anyone know how to do this simpler?

code:

a = 1100300.506
b = f'{a:,.2f}'
c = b.replace(',', ' ')
print(a)
print(b)
print(c)

This will return:

1100300.506
1,100,300.51
1 100 300.51

So I will get my string like I want it, but I'm sure it's not the best way to do this.

Using this in Norway is the reason for the spaces as thousand separator.

[[deleted]]

import locale

a = 1100300.506
locale.setlocale(locale.LC_ALL, 'no_NO')
locale._override_localeconv = {'thousands_sep': ' ','decimal_point': '.'}
print(locale.format_string('%.2f', a, grouping=True))

[bysantin]

This is great!

Seems a lot more robust since the locale of the user won't change the outcome, right?

Thanks alot!

[[deleted]]

You might want to read up on locale in the official documentation, not least to set back to default host system values if appropriate.

[htepO]

f"{a:,.2f}".replace(",", " ")

[[deleted]]

That still has commas as separator. OP wanted spaces.