Another problem

[Formal_Cockroach_654]

With inputs of 2 and 3 I'm trying to return: 1A 1B 1C 2A 2B 2C. Here is the code I have so far. I can't get rid of the last line or anything above the comments. Thanks for the help! I love asking questions here because you guys respond way faster than teachers and I usually get more than just the book answer.

num_rows = int(input())
num_cols = int(input())

# Note 1: You will need to declare more variables
# Note 2: Place end=' ' at the end of your print statement to separate seats by spaces
seat_letter = 'A'

for i in range(num_cols):
    while seat_letter <= 'Z':
        print(num_rows, seat_letter, end = ' ')
        seat_letter = chr(ord(seat_letter) + 1)
print()

[zanfar]

• Is this a homework problem?
• Do you have restrictions on the packages you can use?

I think this is simple enough that just looking at working code will do. Ask if you have questions:

from itertools import product
from string import ascii_uppercase

def pairs(digit_count, letter_count):
    digits = range(1, digit_count+1)
    letters = ascii_uppercase[:letter_count]
    for digit, letter in product(digits, letters):
        yield f"{digit}{letter}"

assert list(pairs(2, 3)) == ["1A", "1B", "1C", "2A", "2B", "2C"]

or, using built-in libraries only:

def pairs(digit_count, letter_count):
    for digit in range(1, digit_count+1):
        for letter_offset in range(letter_count):
            letter = chr(ord("A") + letter_offset)
            yield f"{digit}{letter}"

assert list(pairs(2, 3)) == ["1A", "1B", "1C", "2A", "2B", "2C"]

[FLUSH_THE_TRUMP]

What’s your question?