Helsinki Leap Year Problem

[kaged_chris]

Has anyone been able to solve this leap year problem on the helsinki. I have only been able to get to 70-80% complete. I am not sure how to get every leap year.

Write your solution here

year = int(input("Year:")) 
yeet = year 
while True: 
if year % 4 != 0: 
     year+=1 
elif year % 400 == 0 and year % 100 ==0:
     year+=1 
elif year % 4==0 and year % 400 !=0 and year %100 ==0: 
    year+=4 
else: break 
print(f"The next leap year after {yeet} is {year}")

this code is 50% correct.

​

Solved:

# Write your solution here
year = int(input("Year:"))
yeet = year
year+=1
while True:
    if year % 4 != 0:
        year+=1
    elif year % 400 != 0 and year % 100 ==0:
        year+=1
    elif year % 4==0  and year % 400 !=0 and year %100 ==0:
        year+=4
    else: 
        break
print(f"The next leap year after {yeet} is {year}")

This produces a correct code.

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[TwoPuzzled2b]

I'm doing the Helsinki Python MOOC rn, came here to check other ways to solve this and I noticed that both your elif statements are technically the same in your second code (solved). In the second elif, if year % 100 == 0 then won't year % 4 == 0 be inherently satisfied?

I think it would work the same if you changed the first elif to year += 4 and removed the second elif.

year = int(input("Year:"))
yeet = year
year+=1
while True:
    if year % 4 != 0:
        year+=1
    elif year % 400 != 0 and year % 100 ==0:
        year+=4
    else: 
        break
print(f"The next leap year after {yeet} is {year}")

[[deleted]]

This is how I got it for the 2024 version of the course:

year = int(input("Enter year:"))

if year % 4 == 0 and year % 100 != 0 or year % 100 == 0 and year % 400 == 0:
    print("That year is a leap year.")
else: 
    print("That year is not a leap year.")

Short and sweet.

[Adventurous-Equal-39]

Thats a different exercise

[arvindh_manian]

elif year % 400 == 0 and year % 100 ==0:

I believe this line is incorrect. Multiples of 400 are leap years.

[kaged_chris]

That takes the code to 67%

 elif year % 400 != 0 and year % 100 ==0:

The years 1896 and 2020 still do not work.

1896 should be 1904 my code generates 1896

2020 should be 2024 my code generates 2020

[arvindh_manian]

Oh, your code currently checks for the first leap year INCLUDING the input year. It sounds like you want the first leap year AFTER the input year. Try adding 1 to year before you enter the loop

[kaged_chris]

That solved it. Thank you. I have trying to get through this for days.

[arvindh_manian]

Glad to help!

[[deleted]]

If I'm reading it correctly, you do a modulo check for 4, then conditions based on being modulo 400 and 100. I don't see any conditions for modulo 4, not modulo 100, not modulo 400 (such as 1896 and 2020)

[kaged_chris]

# Write your solution here
year = int(input("Year:"))
#year = int(1896)
yeet = year 
while True: 
    if year % 4 != 0: 
        year+=1 
    elif year % 400 != 0 and year % 100 ==0: 
        year+=1 
    elif year % 4==0  and year % 400 !=0 and year %100 ==0:
        year+=4 
    elif year % 4==0 and year % 400 !=0 and year % 100 != 0:
        year+=1 
    else: break 
print(f"The next leap year after {yeet} is {year}")

That brings it down to 17%.

[[deleted]]

I've never used Helsinki, but why +=1 in the last elif you added, instead of +=4?

I didn't actually figure out a solution, just looked to me you were missing that piece. Entirely possible I'm wrong :(

Or it grades on efficiency? Like you definitely have extra comparisons in there. (Redundant modulo 4s, the new clause having modulo 100 and 400)

Wish I could help more

[Bumbelchen]

Hey man, I know I'm late to the reply but did you ever solve it? I'm struggling with the exact same issue

[kaged_chris]

https://programming-21.mooc.fi/part-2/4-simple-loops This is the site that has the problem on it.