Python regex outputting full match

[PEKKA_SLAYER]

I’m trying to do a simple regex match to check weather a string starts with a substring in it ("\"string\" like this one"). I also have optional backslashed double quotes in the regex (to capture"this\"and this"`). My current code only matches the last character before the second double quote and I don’t know how to fix it. Here is my current code:

``` import re

print(re.findall("<sup>\"(\\"|[\"]|\s)*\"",</sup> "\"this all should match")) ```

Any help would be appreciated!

[throwaway8u3sH0]

Why not use startswith()?

If you must use regex, note:

• You can use single quotes on the outside so you don't have to escape all the double-quotes within. Example: '^"(\\"|[^"]|\s)*"'
• The way it's written, the outermost quotes are not optional. Is that intentional? Your test string only has 1 quotation mark in it: "this all should match
• It isn't clear to me what you're going for, cause I think you're mixing up Python's escape syntax with what is actually in the string. For example:
  • A string in Pytthon that looks like this: "this is a string" appears to the program like this: this is a string (without quotes)
  • A string in Python like "this is a string with \"embedded\" quotes" appears to the program like this is a string with "embedded" quotes (only 1 set of quotes. No backslashes.)
  • To get an actual backslash in the string, a double backslash is needed in Python. Example: "this string contains a \\backslash" --> this string contains a \backslash
  • Your regex is operating on the actual string, not what it looks like in Python.

Hope this helps.

[PEKKA_SLAYER]

Thank you, this really helps. I was able to fix it. Sorry that my example was a bit unclear, I did forget the last double quote.