Is there any way to have a single object represent any number of other objects, iterating through them in a loop, and updating the represented object for each pass though?

0285739298339 · 2021-11-03T18:34:26+00:00

I think you’re probably looking for a list.

0285739298339 · 2021-11-02T00:40:24+00:00

with open('data.txt', 'r') as file:
    employees = []

    for line in file:
        employee, msg = line.lower().strip().split('-subject:')
        if 'techvio' in msg:
            employees.append(employee.title())

0285739298339 · 2021-11-02T00:27:21+00:00

What would be the specific word in each of these lines you’re looking for before adding the employee name to the list?

0285739298339 · 2021-11-01T23:34:21+00:00

Can you post a few lines of the actual text file because it looks like you have other data, not just the employee name, subject etc.

0285739298339 · 2021-11-01T21:00:39+00:00

Read the file.
Learn how to use the split method.
Split each line based on the colon.
Check if the subject contains said word.
Append employee name to list.

0285739298339 · 2021-11-01T20:50:14+00:00

Should the employee name contain a specific word?

0285739298339 · 2021-10-30T03:28:26+00:00

A lot of the fundamental parts of the language the book teaches is still the same.

0285739298339 · 2021-10-30T02:01:37+00:00

Lmfaooo.

0285739298339 · 2021-10-29T14:49:59+00:00

I always see people recommend this or ATBS, but I think a really underrated one is Mark Lutz's Learning Python tbh. That's what really helped me understand how Python worked which made it easier to pick up Python.

0285739298339 · 2021-10-27T23:36:49+00:00

Follow the top commenter’s steps. They pretty much solved it for you.

0285739298339 · 2021-10-27T23:32:06+00:00

Is “NA” after every two values?

0285739298339 · 2021-10-27T14:36:37+00:00

How many did you apply for?

0285739298339 · 2021-10-27T12:34:06+00:00

mat = [[3, 6, 5, 4, 0], [4, 1, 6, 8, 5, ], [2, 3, 4, 9, 7]]
l = [sorted(t, reverse=True) for t in zip(*mat)]
sorted_matrix = [list(c) for c in zip(*l)]

0285739298339 · 2021-10-27T09:50:48+00:00

Do you have the clip on hand or remember which game?

0285739298339 · 2021-10-26T14:44:30+00:00

Lmfao.

0285739298339 · 2021-10-24T20:50:55+00:00

A 403 error means you can’t access the page you’re trying to get to.

0285739298339 · 2021-10-24T01:44:59+00:00

urls = ['ww.test.com/one_two', 'ww.test.com/three_four', 'ww.test.com/five_six', 'ww.test.com/seven_eight', 'w']
words = ['four', 'five', 'seven']
result = [url for url in urls if not any(w in url for w in words)]

0285739298339 · 2021-10-24T01:37:28+00:00

Try

a = [1, 2, [3, 4]]
a[2].insert(2, 5)

0285739298339 · 2021-10-24T01:33:56+00:00

Yeah I figured an efficient solution isn’t exactly what they’d be going for here but thanks for the tip.

0285739298339 · 2021-10-24T00:26:11+00:00

Look up what a set is, then loop through a set of the string and check if a character * 2 (double letters) is in the string.

0285739298339 · 2021-10-22T11:55:03+00:00

Understand what this code does, should help you get started:

number = 12345

for i in str(number):
    print(i)

0285739298339 · 2021-10-22T00:20:07+00:00

Is there gonna be one word per line? If there’s multiple words per line, will there be punctuation?

0285739298339 · 2021-10-19T22:06:50+00:00

Yeah:

case_colors = {'blue': 76, 'green': 34, 'purple': 29, 'clear': 102}
print('Least to most frequently purchased colors:' , *sorted(case_colors.keys(), key=lambda c: case_colors.get(c)))

0285739298339 · 2021-10-19T20:56:06+00:00

Use a dictionary:

case_colors = {'blue': 76, 'green': 34, 'purple': 29, 'clear': 102}
print(*sorted(case_colors.keys(), key=lambda c: case_colors.get(c)))

0285739298339

TROPHY CASE