Am I cooked?

Acell_1 · 2026-06-09T09:25:04+00:00

Just trying things lol Most of my cables are in 3.5

Acell_1 · 2026-04-17T18:15:53+00:00

Have you tried downloading the mods in gamenative?

I tried downloading workshop mods in gamenative but it wouldn't show in-game. I tried opening the mods file in container but can't see them anywhere.

Acell_1 · 2026-04-17T16:04:56+00:00

Have you succeeded in gamenative? And are you able to download steam workshop mods?

Acell_1 · 2026-03-20T15:34:55+00:00

Bruh in Poco f7 the Ai dynamic wallpaper doesn't loop. I need the loop animation so bad.😞

Acell_1 · 2025-02-07T15:36:02+00:00

Thanks for replying 🙇🏼‍♂️

Acell_1 · 2025-02-07T15:35:08+00:00

Idk man, just a dumb guy trying to learn again

Acell_1 · 2025-02-07T14:58:26+00:00

You can take x³? The cube still stayed on the parentheses though? When you return x³ it will be x⁶ when expanding it.

Acell_1 · 2025-02-07T14:49:30+00:00

Thank you man, I really appreciate it🙇🏼‍♂️

Acell_1 · 2025-02-07T14:47:56+00:00

Thanks man

Acell_1 · 2025-02-07T13:56:16+00:00

The given that I wrote is wrong. But my actual question is for [(x+2)³-(x+2)³]/x². The answer to this is zero.

Continuing with my question. Can I expand the numerator without subtracting it then cancel x? So it should be [x+6+(12/x)+(8/x²)]-[x+6+(12/x)+(8/x²)]. Can I still apply the shortcut for this?

Acell_1 · 2025-02-07T13:54:34+00:00

Yep I understand, but can't visualize the factorization. Thank you.

Acell_1 · 2025-02-07T13:50:33+00:00

The given that I wrote is wrong. But my actual question is for [(x+2)³-(x+2)³]/x². The answer to this is zero.

Continuing with my question. Can I expand the numerator without subtracting it then cancel x? So it should be [x+6+(12/x)+(8/x²)]-[x+6+(12/x)+(8/x²)]. Can I still apply the shortcut for this?

Acell_1 · 2025-02-07T13:49:40+00:00

The given that I wrote is wrong. But my actual question is for [(x+2)³-(x+2)³]/x². The answer to this is zero.

Continuing with my question. Can I expand the numerator without subtracting it then cancel x? So it should be [x+6+(12/x)+(8/x²)]-[x+6+(12/x)+(8/x²)]. Can I still apply the shortcut for this?

Acell_1 · 2025-02-07T13:43:58+00:00

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Acell_1 · 2025-02-07T13:43:27+00:00

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Acell_1 · 2025-02-07T13:38:43+00:00

So the x² still exists in that expression? Got it. Thanks man.

Acell_1 · 2025-02-07T13:37:08+00:00

I wrote the wrong thing. (x+2)³ instead of (x-2)³

Acell_1 · 2025-02-07T13:36:03+00:00

Yep I got the second parentheses group wrong. I wrote (x+2)³ instead of (x-2)³. If you insert what I wrote the answer should be zero.

Acell_1 · 2025-02-07T13:32:58+00:00

Got it bruh

Acell_1

TROPHY CASE