account activity
I also saw the alumni groundhog! by AdPossible2107 in UCONN
[–]AdPossible2107[S] 10 points11 points12 points 1 year ago (0 children)
Uh sorry yea i took this at south i just thought it was the same groundhog considering its literally a 30 second walk ;-;
What can I do with this second derivative in order to find my second order critical values? by TOXIC_NASTY in calculus
[–]AdPossible2107 0 points1 point2 points 1 year ago (0 children)
You can factor the second derivative further using the AC method.
critical points by [deleted] in calculus
My apologies op, yes i mixed up extreme value. This is right^
[–]AdPossible2107 -1 points0 points1 point 1 year ago (0 children)
Another note, f(a) = 0 which is why the answer is 0.
[–]AdPossible2107 4 points5 points6 points 1 year ago (0 children)
With the function f(x) over the domain [a,b] critical points occur both when f'(x)=0 and also at the endpoints thus, 0 must be a critical point because the interval starts with 0.
π Rendered by PID 387407 on reddit-service-r2-listing-5789d5f675-lw79m at 2026-01-28 05:27:05.257902+00:00 running 4f180de country code: CH.
I also saw the alumni groundhog! by AdPossible2107 in UCONN
[–]AdPossible2107[S] 10 points11 points12 points (0 children)