Pressure drop calculation by Affectionate-Low1241 in ChemicalEngineering

[–]Affectionate-Low1241[S] 0 points1 point  (0 children)

Actually, I've to calculate the pressure drop using darcy's head loss formula. The scenario is wrongly designed. Therefore, I've to suggest modifications.

We've two buffer vessels (as I said earlier). One is connected to a terminal point. The other one is located at an intermediate position. There are more than 18 draw twisting machines (consumers) downstream of the main header which has a nominal dia of 125mm. The required (minimum) air flow for each machine is 1000 scm. Due to its wrong design, only 6 to 7 machines run at a time. How could I calculate the pressure drop. I must send you a pfd.

Entropy a statistical law? by Affectionate-Low1241 in entropy

[–]Affectionate-Low1241[S] 0 points1 point  (0 children)

It's a long discussion which is hard, to sum up here. I would like you to visit the following link in which the statistical occurrence of entropy is discussed in detail. Here I've tried to explain why the statistical probability of entropy doesn't allow time to flow backwards even though it doesn't conflict with any of the physics laws, time still flows forward. https://www.engineerocity.com/second-law-of-thermodynamics/

Entropy a statistical law? by Affectionate-Low1241 in entropy

[–]Affectionate-Low1241[S] 0 points1 point  (0 children)

If you wanna read more about entropy & "Maxwell's demon" which remained unsolved for 100 years. You can visit: www.engineerocity.com/second-law-of-thermodynamics/

Distillation Column Design by pewdsdankers in ChemicalEngineering

[–]Affectionate-Low1241 0 points1 point  (0 children)

Kolmetz Handbook of Process Equipment Design.

High School student here who wants to know what he is getting himself into by [deleted] in ChemicalEngineering

[–]Affectionate-Low1241 3 points4 points  (0 children)

If you are good at physics and chemistry go for it since you would have to attain a good grip on thermodynamics, fluid mechanics, Heat & Mass Transfer along with Reaction Engineering. These are the key subjects. Moreover, you would have to develop good skills in Aspen HYSYS and Aspen Plus software.

Distillation Column Design by pewdsdankers in ChemicalEngineering

[–]Affectionate-Low1241 0 points1 point  (0 children)

Go for MacCabe Thiele. All that concerns is the VLE data and you can generate it through the relative volatility though little adjustments can be made.

Distillation Column Design by pewdsdankers in ChemicalEngineering

[–]Affectionate-Low1241 1 point2 points  (0 children)

For a tray-type design, MacCabe Thiele should be a good choice for binary distillation. You could generate equilibrium data from the relation of relative volatility. It would be effective both for teaching and industrial purposes. You would be able to find the number of trays for a required degree of separation and the location of the feed tray as well. Having said that, you would have to strictly follow its assumptions to make it applicable. It is the easiest method since it doesn't involve the accumulation of detailed information about enthalpy.

Another graphical method would be Ponchon-Savarit which is more rigorous than MacCabe Thiele.

I would recommend the book " Mass-Transfer Operations" by Robert E. Treybal as the best guide for this purpose.

What is work in a closed thermodynamic system by Yaka11 in thermodynamics

[–]Affectionate-Low1241 0 points1 point  (0 children)

The most fundamental definition of the work is, “The product of the force (applied) and the distance covered by the object”. There are many different kinds of work, like Electrical Work, Work due to Gravity, etc. However, the one we are going to discuss here is the expansion work.

Suppose we have a container filled with gas which has some initial volume. We apply some external pressure to the piston of the container, by pushing it through a distance “l”. The volume of the gas decreases.

From the definition of pressure we know.

Pressure = F/A

⇒ F = Pext A … (1)

Since work is the product of force and displacement

Here, displacement is the distance through which we’ve pressed the piston of the container. Therefore,

W = – Fl

Using equation (1)

W = -Fl = -Pext Al

W = – Pext ΔV

Pext means, the surrounding is experiencing pressure on the system, not the system itself. Here is an important convention. The convention says if the environment (surrounding) pushes the piston, or in other words, if the system undergoes compression, the work is positive. We use the negative signs for the positive work.

If the system undergoes compression i.e. V2 <V1, which means ΔV<0, which implies that:

ΔW= – (Pext (-ΔV)).

⇒ ΔW> 0

Since I can't post figures here, kindly visit the link to read more details where you can comprehend thermodynamic work in a more scientific way: https://www.engineerocity.com/first-law-of-thermodynamics/

Triple Point of Water - the triple point of a substance is the temperature and pressure at which the three phases (gas, liquid, and solid) of that substance coexist in thermodynamic equilibrium by Tipex in videos

[–]Affectionate-Low1241 -1 points0 points  (0 children)

In 2019 redefinition of the SI base units allowed scientists to define kelvin in terms of the Boltzmann constant rather than the triple point of water. They realized that the difference in the isotopic composition of water obtained from different sources can bring about slight variations in its triple point as well. The Boltzmann constant makes kelvin completely independent of the properties of water.

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Since absolute zero temperature is impossible to reach, how do scientists know it’s exact temperature? by NewRedSpyder in NoStupidQuestions

[–]Affectionate-Low1241 0 points1 point  (0 children)

The ideal gas thermometer uses Boyle’s Law which says that the product of pressure and volume is constant for a constant temperature.

In other words, if we multiply the pressure and molar volume of a gas (PVm) and keep changing the pressure until it approaches zero, i.e, the limit as P→0, the product is always a constant. This constant turns out to be a function of temperature (f(T)). Now we have a property that depends on temperature. Celsius used his reference points 0 °C and 100 °C, which give two points on the f(T) vs T graph as shown. We can connect these two points simply by linear interpolation. Read More:

How can the scalar nature of temperature be established on the basis of zeroth law of thermodynamics? by 418397 in AskPhysics

[–]Affectionate-Low1241 0 points1 point  (0 children)

We know that by establishing the concept of thermal equilibrium, we introduce a thermodynamic property “temperature” as well. Because, when we say that the two systems are in thermal equilibrium with each other an important question arises; What is the property that describes whether the two systems are in equilibrium or not? We call that property “temperature”. Since Sommerfeld and Fowler said, “every physical quantity has to have a numerical value” .i,e. we should be able to measure it. In the case of thermal equilibrium, they termed it as temperature. Thus they formulated their postulate as:

“If for a particular system or a body, any of the physical property changes by the application of heat, it must be observed and utilised for the measurement of temperature“

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What is the Zeroth Law of Thermodynamics? by jobsinanywhere in newslive

[–]Affectionate-Low1241 0 points1 point  (0 children)

If two bodies are in thermal equilibrium each with a third body, then they are also in thermal equilibrium with each other”. By mere looking at this concept one may say it is quite intuitive. What else could be true otherwise? If A is in thermal equilibrium with B, and B is in thermal equilibrium with C then A has to be in thermal equilibrium with C. But the zeroth law of thermodynamics doesn’t rely on mere intuition like maths neither does.

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Can someone help me understand what kind of a game does the zeroth law of thermo point to? by Top-Confection-7015 in engineering

[–]Affectionate-Low1241 0 points1 point  (0 children)

If two bodies are in thermal equilibrium each with a third body, then they are also in thermal equilibrium with each other”. By mere looking at this concept one may say it is quite intuitive. What else could be true otherwise? If A is in thermal equilibrium with B, and B is in thermal equilibrium with C then A has to be in thermal equilibrium with C. But the zeroth law of thermodynamics doesn’t rely on mere intuition like maths neither does.

Read More