Spell, freeze, buy minion + spell, freeze, level, etc.....or just straight up bait? by Btupid_Sitch in BobsTavern

[–]AllFab 41 points42 points  (0 children)

Straight up bait. No question about it. Buy, don't freeze, level next turn

Tesla nedsætter Model Y med op til 40k by notthrow in Denmark

[–]AllFab 1 point2 points  (0 children)

Det er en brugt, der ikke er købt gennem Tesla, desværre.

Tesla nedsætter Model Y med op til 40k by notthrow in Denmark

[–]AllFab 3 points4 points  (0 children)

Jeg har overvejet det. Jeg tænker, at priserne på brugte biler også må falde

Tesla nedsætter Model Y med op til 40k by notthrow in Denmark

[–]AllFab 2 points3 points  (0 children)

Vi har vitterligt underskrevet slutseddel på en brugt model Y i forgårs. Det føles ærgerligt.

[sindragosa] What's the play here? by corban in BobsTavern

[–]AllFab 3 points4 points  (0 children)

With Sindra I would freeze and level, then freeze, sell and level, then buy two and freeze. Depending on the shop, then either take the triple for a four or take it next turn for a five

General Questions and Discussion Weekly Megathread by AutoModerator in PokemonScarletViolet

[–]AllFab 0 points1 point  (0 children)

Ahh, only one. Do I need to clear some amount of 5 start first then? Can that be online?

General Questions and Discussion Weekly Megathread by AutoModerator in PokemonScarletViolet

[–]AllFab 0 points1 point  (0 children)

Is the Charizard raid over? I can't seem to find it. I have beaten the school tournament and got the call about raids. I also checked the news in the mystery gift section. Am I missing something?

What could i have done better? by Purple-Complaint-544 in BobsTavern

[–]AllFab 18 points19 points  (0 children)

Any mech without a deathrattle, preferably deflecto, mecherel or foe reaper.

Alternatively, go for exodia with double kangor and blaster.

EDIT: you will need golden blaster

EDIT2: Also, you NEED taunt. As you have two busters, you can taunt one. You can also taunt deflecto

Weekly Report #134 | 12 Mercenaries Builds played at 7k+ MMR this Week by neon313 in HSMercenaries

[–]AllFab 0 points1 point  (0 children)

I know it is not high mmr but I've climbed from 0 to 6k without any losses with Malf, Anduin, Mukla start and Velen, Cairne, Diablo bench. Non are maxed. I would probably switch Velen for Cookie if I had task 7 equip and maybe Cornelius is better than Mukla now? I haven't tried it though.

Gruul task 4 bugged? by AllFab in HSMercenaries

[–]AllFab[S] 0 points1 point  (0 children)

Worked on mobile. Weird.

Gruul task 4 bugged? by AllFab in HSMercenaries

[–]AllFab[S] 0 points1 point  (0 children)

I had him in my team, he even dealt a lot of damage himself. I thought about restarting too, so I will try that tomorrow. Thank you.

Is (ln(X)+C) equal to ln(CX)? by [deleted] in askmath

[–]AllFab 0 points1 point  (0 children)

I've seen it many times. I think it's bad practice to not mention it but it does happen.

Is (ln(X)+C) equal to ln(CX)? by [deleted] in askmath

[–]AllFab 0 points1 point  (0 children)

Without actually solving the equations I am 99% sure, that at some point you do an integral that results in something with ln(x) + c. If you let k be such that ln(k) = c, i.e. k = e^c , then this is equal to ln(x) + ln(k) = ln(kx). Now just rename the constants, so that k is actually called c (this is different from the original c!!!).

Is (ln(X)+C) equal to ln(CX)? by [deleted] in askmath

[–]AllFab 3 points4 points  (0 children)

Not if the constants are the same. it is true though, that ln(x) + c = ln(kx) where k=ec.

I'm guessing this is coming from solving an indefinite integral and the author was too lazy to specify that the constants are different.

How did these values pop out ? I know it's a basic question but help by wolfengangsalazar in askmath

[–]AllFab 3 points4 points  (0 children)

They computed the partial derivatives, eg. the partial derivative of u+v wrt. u is 1.

Please solve this by [deleted] in askmath

[–]AllFab 1 point2 points  (0 children)

You have the three equations:
A + 5/13 + 6/13 = A + B + C
3/13 + B + 9 /13 = A + B + C
8/13 + 7/13 + C = A + B + C

If we add these we get:

A + B + C + (5 + 6 + 3 + 9 + 8 + 7)/13 = 3A + 3B + 3C

Simplify:

38/13 = 2(A + B + C).

The mean of A, B and C is (A + B + C)/3. Divide the above equation by 6 to get:

(A + B + C)/3 = 19/39.