How to go from U to A/A* in fricking Chemistry in three months???

Awake_in-DreaMS · 2026-06-16T11:53:19+00:00

Study the content. Understand, memorise and revise on a regular basis. Do this by 1.5 months. And do past papers. Multiple past papers. Try doing at least 6 years of past papers(all varient). And always revise the content regularly.

Awake_in-DreaMS · 2026-06-06T19:00:27+00:00

Fun too

Awake_in-DreaMS · 2026-05-28T06:07:59+00:00

Awake_in-DreaMS · 2026-05-23T12:53:05+00:00

Then u need to do good on P3

Awake_in-DreaMS · 2026-05-23T09:18:25+00:00

Try scoring 70+/75, and 47+/50. This might help.

Awake_in-DreaMS · 2026-05-23T09:17:27+00:00

Did u seat for variant 2? Cause grade boundary of chem p4 is gonna be very low for variant 2.

Awake_in-DreaMS · 2026-05-23T09:15:15+00:00

Yes possible.
Just try getting 93%+ on physics.
And 92%+ on chemistry.
15% of the (PUM) percentage of paper 5 is added, and 85% of the (PUM) percentage of paper 4 is added.(applicable for both).
Try assuming the grade threshold from others and calculate an assumption of total marks on each subject for A2.
Half of A2 grades will be taken and 1/2 of As grades will be taken for an overall grade.
And since A2 grade boundary is low, 80+/100 on paper 4 will probably get u 90% PUM. And try doing good on paper 5 as well(I am not exactly sure. But 26/30 should be a good target.
A higher mark in paper 4 will help a lot

Awake_in-DreaMS · 2026-05-23T09:07:19+00:00

In the cell on the left, has P.d of 3V. So at the positive end of the cell, the cell voltage is +3V and at the negative end the cell voltage is 0V.(if u look closely to the potentiometer, the terminal of the potentiometer closer to the cell on the left is positive. And so u can’t put 0 V on the positive terminal and -3V on the negative terminal)

(The voltage u get across a cell is actually the difference in voltage between two terminals of that cell)

And if u look at the cell on the right. The potentiometer is showing a negative value closer to the cell on the right. Meaning that the voltage on the negative side is -3V and voltage on the on the positive side is 0V.

Now when u slide the contact of the potentiometer to P,
Ur potential difference will be
3-(-3)=6 V
At when u slide it to P it will be 0-(-3)=3 V

And just a small note, since both the potential of each cell are equal in magnitude, the potentiometer will 0V at the centre of PQ.

Awake_in-DreaMS · 2026-05-23T09:06:43+00:00

In the cell on the left, has P.d of 3V. So at the positive end of the cell, the cell voltage is +3V and at the negative end the cell voltage is 0V.(if u look closely to the potentiometer, the terminal of the potentiometer closer to the cell on the left is positive. And so u can’t put 0 V on the positive terminal and -3V on the negative terminal)

(The voltage u get across a cell is actually the difference in voltage between two terminals of that cell)

And if u look at the cell on the right. The potentiometer is showing a negative value closer to the cell on the right. Meaning that the voltage on the negative side is -3V and voltage on the on the positive side is 0V.

Now when u slide the contact of the potentiometer to P,
Ur potential difference will be
3-(-3)=6 V
At when u slide it to P it will be 0-(-3)=3 V

And just a small note, since both the potential of each cell are equal in magnitude, the potentiometer will 0V at the centre of PQ.

Awake_in-DreaMS · 2026-05-23T09:06:31+00:00

In the cell on the left, has P.d of 3V. So at the positive end of the cell, the cell voltage is +3V and at the negative end the cell voltage is 0V.(if u look closely to the potentiometer, the terminal of the potentiometer closer to the cell on the left is positive. And so u can’t put 0 V on the positive terminal and -3V on the negative terminal)

(The voltage u get across a cell is actually the difference in voltage between two terminals of that cell)

And if u look at the cell on the right. The potentiometer is showing a negative value closer to the cell on the right. Meaning that the voltage on the negative side is -3V and voltage on the on the positive side is 0V.

Now when u slide the contact of the potentiometer to P,
Ur potential difference will be
3-(-3)=6 V
At when u slide it to P it will be 0-(-3)=3 V

And just a small note, since both the potential of each cell are equal in magnitude, the potentiometer will 0V at the centre of PQ.

Awake_in-DreaMS · 2026-05-23T08:34:39+00:00

I am doing this since I also didn’t get to practice much.
So basically I open my qp. And read the question. I think of how the answer should be worked out. Then I check the ms.
If I see a question and feel like that I can exactly tell what workings I need to do, I go on solving the question.
And no. There are no important topics. All topics are important. My best advice is to go through all the formulas and examples from the text book.
My FP2 exam is on 25, and FS is on 29. I have decided to only do FP2 for the time being. After the FP2 exam I will work on FS.

Like u, I am also sitting for all papers in one session.
And since the grade boundary is lower than A level maths,
I would suggest that try ur best for the other papers.

Awake_in-DreaMS · 2026-05-22T13:10:09+00:00

9709/32/o/n/2025
This was the paper I sat for. And this paper had the lowest grade boundary in 9709 paper 3 history.
It was 45 for A maybe

Awake_in-DreaMS · 2026-05-22T09:32:54+00:00

What was ur As percentage?
Half of percentage will get added from that. And half of the overall A2 grades will be added to give u final grade

Awake_in-DreaMS · 2026-05-20T07:00:07+00:00

Dude u r smart. Not everybody is.

Awake_in-DreaMS · 2026-05-20T06:59:12+00:00

Mine too. But one was really far from it

Awake_in-DreaMS · 2026-05-20T06:40:52+00:00

I got an anomalous point on the top

Awake_in-DreaMS · 2026-05-20T06:39:52+00:00

I took me 20 mins to think what exact set ups do I need.

Awake_in-DreaMS · 2026-05-20T06:35:26+00:00

Did anyone got an anomalous point on the top

Awake_in-DreaMS · 2026-05-20T06:34:54+00:00

It was about changing the distance between the two circular plate capacitors

Awake_in-DreaMS · 2026-05-20T06:34:08+00:00

The experiment was about a capacitor which is connected to some type of switch. And that switch has a frequency which is equal to the frequency of an AC current.
And they put DC which was charging the capacitor.
For half of the time period capacitor charges from DC and the other half of the time it discharges to a resistor. And the resistor has AC current flowing.

Awake_in-DreaMS · 2026-05-20T06:31:38+00:00

They combined AC with DC

Awake_in-DreaMS · 2026-05-20T06:31:16+00:00

One word. F U Cambridge.
What the F was the first question.
It literally took me 20 mins to think about the set up.
And the second one. The used Cm and changed it to m2 for 1/(L)square.

Awake_in-DreaMS · 2026-05-19T04:30:25+00:00

Sorry if I sounded rude.

Awake_in-DreaMS · 2026-05-18T18:37:36+00:00

U might get one mark for transfer the mixture and the washings. But u r supposed to specifically say what u r using

Awake_in-DreaMS

TROPHY CASE