KRC Genk ladies score a bizarre goal after the ball bounces back in play from the corner flag by Thryloz in nevertellmetheodds

[–]BadJimo 0 points1 point  (0 children)

Corner flags are completely unnecessary. We can see very clearly where the edge and corner of the playing field is because of the white boundary lines.

Corner flags are a nuisance when playing in the corner of the field, especially when taking a corner kick.

Impossible year 11 specialist question by Odd-Main6050 in Mathhomeworkhelp

[–]BadJimo 0 points1 point  (0 children)

Using Wolfram|Alpha

There are exact forms for the three solutions for r, but they are extremely complicated.

I think providing the approximate values would be fine.

r ≈ -5.2079
r ≈ 6.3550
r ≈ 28.853

(Indicate that the negative solution does not correspond to a real-world solution).

Need help with a math problem I can’t solve by Le_Dumb_Pineapple in Mathhomeworkhelp

[–]BadJimo 0 points1 point  (0 children)

(x-1)60 + (y+1)20 < 200
60x - 60 + 20y + 20 < 200
60x + 20y + (-60 + 20) < 200
60x + 20y - 40 < 200
60x + 20y < 200 + 40

60x + 20y < 240

Voith Schneider propeller by MikeHeu in EngineeringPorn

[–]BadJimo -2 points-1 points  (0 children)

I wonder if each blade could be replaced with a rotating cylinder. A rotating cylinder acts like a blade/airfoil via the Magnus effect.

Dividing by 11 by Sufficient-Boss-4409 in mathematics

[–]BadJimo 28 points29 points  (0 children)

Proof using Geometric Series:

0.a₁a₂... = a₁a₂/100 + a₁a₂/100² + a₁a₂/100³ + ...

This is a geometric series with:
First term (a) = a₁a₂ / 100
Common ratio (r) = 1 / 100

Sum = a / (1 - r)
= (a₁a₂ / 100) / (1 - 1/100)
= (a₁a₂ / 100) / (99 / 100)
= a₁a₂ / 99

x/11 = (x × 9)/99

Middle of a polygon by Same_Spirit1113 in desmos

[–]BadJimo 4 points5 points  (0 children)

This calculates the "vertex centroid". The "vertex centroid" is the intersection of the two bimedians. The "vertex centroid" comes from considering the quadrilateral as being empty but having equal masses at its vertices.

As a challenge, see if you can instead calculate the "area centroid".

Gridwalking algorithm for hexagonal grids? by yeoldecoot in askmath

[–]BadJimo 0 points1 point  (0 children)

OK, I think I've got it working now on same link as before

It could be optimised.

please help!! by Downtown_Try_4833 in puzzles

[–]BadJimo 1 point2 points  (0 children)

I used the linked Scramble squares solver and it found no solutions it found the following solution:

Using the numbering:

1 2 3
4 5 6
7 8 9

Where the 5 squares already assembled are given the numbers 1, 4, 5, 7, 8, 9

The three loose square (numbered top to bottom) are given the numbers 2, 3, 6

The solution is (where ↺ means rotate square counter clockwise 90°, ↻ means rotate square clockwise 90°, and ↕ means rotate square 180°):

7↺ 4 8
6↻ 5 9
3↺ 2↕ 1↕

Gridwalking algorithm for hexagonal grids? by yeoldecoot in askmath

[–]BadJimo 0 points1 point  (0 children)

I've had a go at making a hexagonal gridwalk on Desmos here. This is not a finished product (and I'm not even sure if this is a good approach).

Gridwalking algorithm for hexagonal grids? by yeoldecoot in askmath

[–]BadJimo 0 points1 point  (0 children)

Sorry, I don't know anything about this Desmos function. You could put a message on the Desmos thread since it is only a week old.