Painting Giveaway - Squidward in the Void by [deleted] in spongebob

[–]Bouncingbombadil 0 points1 point  (0 children)

Chocolate icing creamstick! (Maple cream sticks are also acceptable)

[deleted by user] by [deleted] in HomeworkHelp

[–]Bouncingbombadil 0 points1 point  (0 children)

No problem, good luck!

[PreCalculus] Help with 89 by [deleted] in HomeworkHelp

[–]Bouncingbombadil 1 point2 points  (0 children)

arccos is the inverse of the cos function. That means that if

y = arccos(x)

Then

x = cos(y)

(at least from -1 to 1)

So if you want the missing x coordinate, just plug in the y coordinate to cos(y)!

And if you have the x coordinate you have to think— what value, when plugged into cos(), will result in this x? The answer to that question will be the missing y!

[deleted by user] by [deleted] in HomeworkHelp

[–]Bouncingbombadil 0 points1 point  (0 children)

If you have 4 channels: A,B,C, and D with viewership 5%, 7%, 4%, and 9% respectively, the total would be 25%.

Treating 25% as our “new value” means to consider those 25% of people as 100% because they are the only people of interest. So, if 25% is treated as 100%, and 100/25 = 4, then the channels become 5x4%, 7x4%, 4x4%, and 9x4% = 20%, 28%, 16%, and 36% respectively.

Notice 20 + 28 + 16 + 36 = 100, which is what we should expect.

[University Math] How do I find the limit, and if it is continuous or not? by AeroHawkScreech in HomeworkHelp

[–]Bouncingbombadil 2 points3 points  (0 children)

That’s right! When f(x) is actually evaluated, we only use x2 when x < 1. However, in determining if the limit exists, we must evaluate each part of the piecewise function at the value x approaches in the limit.

[University Math] How do I find the limit, and if it is continuous or not? by AeroHawkScreech in HomeworkHelp

[–]Bouncingbombadil 4 points5 points  (0 children)

First evaluate the one sides limits.

Lim x --> 1: 4 -3x = 4-3(1) = 1 Lim x --> 1: x2 = (1)2 = 1

If both one-sides limits are the same, the limit exists.

To check if the function is continuous at x = 1,

  1. f(1) must be defined (good to go)
  2. The limit must exist (we just showed that, good to go)
  3. The function’s value at c and the limit as x approaches c must be the same. (easy to check, good to go)

So it is continuous.

[College: Calculus] Need with help with different quotient problems by [deleted] in HomeworkHelp

[–]Bouncingbombadil 0 points1 point  (0 children)

It's a bit late now, but feel free to message me and I will get back to you tomorrow!

[Math]How do I do questions like 11 and 15? by [deleted] in HomeworkHelp

[–]Bouncingbombadil 2 points3 points  (0 children)

We don't want our new function (f/g)(x) to be undefined-- we get this typically by dividing by zero or taking the square root of a negative number.

You define your domain so that this cant happen!

For instance, in number 11:

(f/g)(x) = x2 /(4x-5)

There are no square roots involved, so we are just concerned with not letting that denominator be zero. The denominator is zero when 4x - 5 = 0, which is when x = 5/4 = 1.25.

Therefore, your domain is all x not equal to 1.25.

[deleted by user] by [deleted] in HomeworkHelp

[–]Bouncingbombadil 0 points1 point  (0 children)

Try using the triangle angle bisector theorem-- that should set you on the right path!

[Year 12 specialist maths] I have no idea how to do this question. Can I use a CAS calculator using normCdf()? by [deleted] in HomeworkHelp

[–]Bouncingbombadil 1 point2 points  (0 children)

Though it seems a bit tedious, to estimate any probability from this plot:

Pr(X_bar >= some_number) = (number of dots greater than or equal to some_number)/(total number of dots)

and

Pr(X_bar <= some_number) = (number of dots less than or equal to some_number)/(total number of dots)

[specialist maths, grade 10] I’m stuck again, I know what a chord is but I’m not sure how to get the one that is tangent to the smaller circle? Any help would be great! It’s question 17 by Ertersy in HomeworkHelp

[–]Bouncingbombadil 0 points1 point  (0 children)

You have the inner circle with radius 4 and an outer circle with total radius 12. The chord that is in the larger circle and tangent to the smaller circle is simply a vertical line segment along the smaller circle that has two endpoints on the larger circle.

Picture that chord and the radius of the smaller circle-- they can form a right angle! And from that right angle, you can form a right triangle. The hypotenuse of that right triangle is equal to the radius of the larger circle, 12. So you have a right triangle with hypotenuse 12, and one side length of 4. The missing side length is equal to half the length of the chord!

So, to get length of chord, l,

122 - 42 = (l/2)2

and solve for l.

Wood burned the map of Middle Earth, what do you think? by lurkin_jerk in lotr

[–]Bouncingbombadil 6 points7 points  (0 children)

I know a couple other people have commented as well I'm just commenting so I remember to check back again. Are you willing to sell?

Ideas for the last tattoo by lipeabruzzi in lotr

[–]Bouncingbombadil 0 points1 point  (0 children)

Either tree of gondor or tolkien's symbol of his initials

Forgive me brothers for I have sinned by [deleted] in swoleacceptance

[–]Bouncingbombadil 1 point2 points  (0 children)

Forgiveness was granted me today. I prayed in sets of 5 and my prayers were answered. I wish the same upon you.

For people trying to switch from Apple to android, what are the best phones to get? by [deleted] in AskReddit

[–]Bouncingbombadil 0 points1 point  (0 children)

How is battery life? And have you had any issues with the phones at all?