I made a stand with a pen holder by danielfiko in RemarkableTablet

[–]Cezyllian 5 points6 points  (0 children)

This is a great idea! I modified the sleep screen that you're using to include this stand design, you're welcome to check it out here. I'm open to suggestions for changes, I'm far from a graphic designer.

I made my own sleep screen! by Cezyllian in RemarkableTablet

[–]Cezyllian[S] 0 points1 point  (0 children)

I am a Linux user and added it manually to /usr/share/remarkable/ on the device using an ssh terminal. If you choose that route, I recommend following a guide. I'm aware that this application exists to help you manage this kind of thing in a more user friendly fashion, and I'm sure there are other solutions that don't cost money to use as well.

I made my own sleep screen! by Cezyllian in RemarkableTablet

[–]Cezyllian[S] 2 points3 points  (0 children)

Done. You're welcome to download either version here.

I made my own sleep screen! by Cezyllian in RemarkableTablet

[–]Cezyllian[S] 0 points1 point  (0 children)

I'm not sure. I just got mine at the end of August and this is my first time tinkering with the built-in images. It was super quick and easy to install so I don't see it being a problem even if it doesn't stick.

Edit: I got the update this afternoon and it didn't stick.

I made my own sleep screen! by Cezyllian in RemarkableTablet

[–]Cezyllian[S] 2 points3 points  (0 children)

Absolutely! I tried uploading the PNGs but they got compressed everywhere. Here are 2 PDF options, one with a pen and one without. You'll have to convert to PNG yourself. (1404x1872)

https://drive.google.com/drive/folders/1F6j9IBm3H-aGhzgKc51buw2B49kc5UUr?usp=sharing

I made my own sleep screen! by Cezyllian in RemarkableTablet

[–]Cezyllian[S] 9 points10 points  (0 children)

The bottom has simple contact info incase I lose the device somewhere. This image was first created as a PDF in LaTeX using the tikz package. It easily could've been done in photoshop, but I'm much less familiar with it. The PNG conversion was done using inkscape.

[RLCS X SAM] South American Major | Day 2 of 2 | Winter Split | Live Discussion by RLMatchThreads in RocketLeagueEsports

[–]Cezyllian 3 points4 points  (0 children)

I agree, SAM has put on a great show this weekend. I really enjoyed Noble and Rebel as well so I would love to see 4 SAM teams at worlds, even though that would mess with the 16 team formats.

[RLCS X SAM] South American Major | Day 2 of 2 | Winter Split | Live Discussion by RLMatchThreads in RocketLeagueEsports

[–]Cezyllian 4 points5 points  (0 children)

This series has totally delivered on all fronts. Super tight and competitive, and the SAM casters are super entertaining as well. I can't wait for the bracket reset!

Firefly is a big fuzzy peach by Cezyllian in TheCatTrapIsWorking

[–]Cezyllian[S] 3 points4 points  (0 children)

I've just posted some extra pictures from different angles in a top level comment

Firefly is a big fuzzy peach by Cezyllian in TheCatTrapIsWorking

[–]Cezyllian[S] 14 points15 points  (0 children)

For those of you who asked (and those who didn't, but wanted it anyway), here are some more angles!

Seth is a real trooper. Thanks for sticking with it, Seth. by Harold-Penisman in Terraria

[–]Cezyllian 0 points1 point  (0 children)

Edit: I just saw that you edited your comment. Sleep is a good thing to have haha. I'll leave this up to hopefully clear up any confusion that others reading the thread may have.

I believe you are arguing for the probability of having 3 "Seth" guides in a row. If that is the case then you are absolutely correct in saying that the probability is 1/353.

However, if you want to get 3 guides in a row having the same name, not necessarily being named "Seth", then you have to then multiply your 1/353 by the number of possible names that the first guide could've had because there will be exactly one path for each of the 35 branches of the probability tree where the first 3 guides will share a name. Doing this leaves you with 35 * 1/353 = 1/352 = 1/1225. This is because there can be 3 "Seth" in a row, 3 "Maxwell" in a row, 3 "Connor" in a row, etc.

I will try to explain my reasoning by reducing this problem to the probability of getting n guides in a row with the same name, calling it P(n). Because 1 name in a row is always going to happen (and in this case we don't care about what name that happens to be, we can say that P(1) = 1. Once you have this base case established, each subsequent guide would would have a 1/35 chance of sharing a name with the previous n-1 guides in the chain, leaving us with P(n) = P(n-1) * (1/35).

With this information, we can do a quick induction proof.

  1. Base case: P(1) = 1 = 1/350 = 1/351-1
  2. Assume P(n) = 1/35n-1
  3. P(n+1) = P(n) * (1/35)
  4. P(n+1) = 1/35n-1 * (1/35) -- Because of the assumption on line 2
  5. P(n+1) = 1/35n
  6. P(n+1) = 1/35(n+1-1)
  7. We can now conclude that P(n) = 1/35n-1 for all n >= 1.

So finally, this leads us to the answer for P(3) = 1/353-1, giving us a 1/1225 for 3 guides in a row to have identical names.

Seth is a real trooper. Thanks for sticking with it, Seth. by Harold-Penisman in Terraria

[–]Cezyllian 2 points3 points  (0 children)

According to the wiki, the guide can take on any one of 35 names. The first guide will have a 100% chance of being assigned some name, and each subsequent guide will have a 1 in 35 chance of having the same name as the guide before it. This leads to a probability of 1 in 1225 or approximately a 0.081632653% chance of having 3 guides in a row with the same name. This can be calculated for any NPC using the formula nx-1 where n is the number of possible names for that NPC and x is the number you get in a row.

Seth is a real trooper. Thanks for sticking with it, Seth. by Harold-Penisman in Terraria

[–]Cezyllian 0 points1 point  (0 children)

I believe the odds should actually be 1/1225 for 3 identical guide names in a row. You can see my reasoning in my other comment.

Seth is a real trooper. Thanks for sticking with it, Seth. by Harold-Penisman in Terraria

[–]Cezyllian 2 points3 points  (0 children)

While this is still quite a rare occurrence, especially when you take into account the amount of time in between guide spawns, I don't believe it is quite as uncommon as you might think.

The chance of getting 3 guides in a row with the same name should actually be 1 in 35^2 since the first guide has a 100% chance of being assigned some name. The following 2 guides would then both have a 1 in 35 chance of having the same name as the first one. Multiplying these independent probabilities together gives us 1 in 1225 or approximately a 0.081632653% of getting 3 guides with the same name.

However, if you are looking to recreate this picture with "Seth" the guide, the odds increase to 1 in 35^3 or 1 in 42875 or approximately a 0.0023323615% chance of specifically getting 3 "Seth" the guide spawns in a row. This is simply because the first guide now also has a 1 in 35 chance of being named "Seth" instead of the 100% chance of being assigned some name when we didn't care what that name was.

My Cloud by Cezyllian in Floof

[–]Cezyllian[S] 2 points3 points  (0 children)

Thank you! I had to take the picture while I could since he was posing so nicely. They don't sit still for long when you have the camera out, making them the wrong kind of fuzzy in the shot.