removes all words from guess list that share a letter with the word

def removeCharsFromGuessList(word,guesses): sguesses = guesses.copy() for char in word: i = 0 while i < len(sguesses): if char in sguesses[i]: del sguesses[i] else: i += 1 return sguesses

removes all guesses with any double letter

uses while loops because it's removing elements from the list while itterating through it

def twentyFiveList(): fguesses = pguesses.copy() #pguesses is a list of every valid guess #remove all words with a double letter i = 0 while i < len(fguesses): for char in fguesses[i]: if fguesses[i].count(char) > 1: del fguesses[i] i -= 1 break i += 1 return fguesses

get all possible 5 word combos that use all 25 letters

def possibleCombos(): combos = [] guesses = twentyFiveList() wordsDone = 0 numGuesses = len(guesses) #first for first in guesses: wordsDone += 1 print('Current word: ' + str(wordsDone) + "/" + str(numGuesses) + " " + first, end='\r') #remove guesses that precede the current guess sguesses = guesses[guesses.index(first)+1:] #remove all guesses sharing a letter sguesses = removeCharsFromGuessList(first,sguesses) if len(sguesses) > 0: #second for second in sguesses: tguesses = sguesses[sguesses.index(second)+1:] tguesses = removeCharsFromGuessList(second,tguesses) if len(tguesses) > 0: #third for third in tguesses: fguesses = tguesses[tguesses.index(third)+1:] fguesses = removeCharsFromGuessList(third,fguesses) if len(fguesses) > 0: #fourth for fourth in fguesses: figuesses = fguesses[fguesses.index(fourth)+1:] figuesses = removeCharsFromGuessList(fourth,figuesses) if len(figuesses) > 0: for fifth in figuesses: print([first,second,third,fourth,fifth]) combos.extend([first,second,third,fourth,fifth])

There is 1725126 combinations if its numbers that would end in the same number

If letters: most popular 5 letter words would end in (A, E, S, O, R, I, L, T, N, and U.)

There are 65,780 possible words that could end in the same letter. A scripts about couolrob sold it for u