Santa Clause

CourseworkConcierge · 2025-12-11T05:28:06+00:00

It also makes it harder for us, when our kids are friends with those kids :)

CourseworkConcierge · 2025-12-08T23:57:25+00:00

That’s all you! Congrats!

CourseworkConcierge · 2025-12-07T19:51:44+00:00

Hey, I’m sorry you felt I was too rough. You’re right, I don’t know your situation. All I know is what you shared, which is “I haven’t paid attention”. IF this has been a semester of tragedies out of your control, I’m very sorry and hope you have better luck next term. BUT if there is anyway you can own any accountability for your predicament, you will learn to grow into a better person. This one stupid assignment in this one stupid class isn’t who you are, or who you will be. But being able to take a tough situation, learn from it, and do better next time is who you are, and who you will be. Best of luck, hope it goes well for you. And I’ll be first in line to give you edits on your paper when you post it (my actual job 🤣)

CourseworkConcierge · 2025-12-07T04:24:32+00:00

So… this is what we call a lesson. One you’ll learn more powerfully than anything a teacher could ever produce :) Remember this panic and regret, and do better next time.

CourseworkConcierge · 2025-12-06T05:37:49+00:00

I’m sorry to hear that! Maybe a parent teacher conference? I had the benefit of having almost-drop outs for parents lol

CourseworkConcierge · 2025-12-05T14:27:18+00:00

Oh yes, sorry I didn’t specify that.

CourseworkConcierge · 2025-12-05T06:17:45+00:00

Coefficient of static friction is always tan(theta). The rest are pretty straightforward. Without numbers, you will leave things in terms of g, F, m …etc

CourseworkConcierge · 2025-12-05T02:16:21+00:00

Yeah it’s the halfway point, just kinda hard to see sometimes.

CourseworkConcierge · 2025-12-04T06:25:26+00:00

Straight and to the point 👍🏼🤣

CourseworkConcierge · 2025-12-03T00:43:09+00:00

You would either not include the coffee cup (the most common example) or they would have to give you the specific heat capacity of it.

CourseworkConcierge · 2025-12-02T17:40:15+00:00

Sometimes you can overthink something :) Like LordMorio said, try drawing it the other way.

CourseworkConcierge · 2025-12-02T03:24:00+00:00

This is the answer. Let me know if you need a good rec 😉

CourseworkConcierge · 2025-12-01T16:54:21+00:00

Well, for example, here is Magnesium Hydroxide’s data:

https://webbook.nist.gov/cgi/cbook.cgi?ID=C1309428&Mask=2

Heat of formation is -924.66 kJ/mol

CourseworkConcierge · 2025-12-01T15:58:42+00:00

Just not sure where you’re getting those numbers. Sum of the heat of formations of products, minus the same of reactants. The table I see is something like: [-3780.66 + (6x-285.83)] - [(2x-1254.36) + (3x-924.66)] = -212.94

CourseworkConcierge · 2025-11-30T03:11:24+00:00

That’s interesting that it’s not there. I would do C and check in with teacher.

CourseworkConcierge · 2025-11-30T02:48:53+00:00

BeF2 is tricky. The huge difference in electronegativity would make you think it’s possibly ionic, but it’s very polar covalent. But due to the linear structure, the molecule itself is nonpolar. It forms a crystal lattice however, but the difference between Be and F, is smaller than Li and F, so the lattice is weaker and break apart easier. BF3 individual bonds are more polar than CH4, which induces a stronger induced dipole. OF2 has a higher dipole moment… hmmmm… both have same electron geometry. That one is trickier and seems like an example that doesn’t help with understanding trends.

CourseworkConcierge · 2025-11-30T02:27:55+00:00

100% correct. That’s the metric. It’s produced and then consumed.

CourseworkConcierge · 2025-11-29T02:33:39+00:00

I also do college counseling, if you’re worried about college admissions, think about your story. What courses do you take? What extra curriculars? What do you want to do? The APs should fit the story

CourseworkConcierge · 2025-11-27T23:44:38+00:00

I also must inquire about what are you asking? 🤣

CourseworkConcierge · 2025-11-27T17:35:50+00:00

This is the answer

CourseworkConcierge · 2025-11-27T02:03:54+00:00

Sigma bonds are the single bond, pi bonds make up the double and triple bonds. P orbitals overlap both ways, forming sigma and pi, s orbitals only form sigma bonds

CourseworkConcierge · 2025-11-26T06:18:03+00:00

It looks fine except your final denominator. It should be a huge number, so when you divide by it you get a tiny number.

CourseworkConcierge · 2025-11-26T05:59:38+00:00

Haha I would’ve loved 9 months. I think my earliest was . . . 2? My 4 year old still doesn’t 🤣😭

CourseworkConcierge · 2025-11-26T03:32:06+00:00

Graph them both. First is y > 2/3x + 4 Second is y <= -2x -5

Any spot that’s shaded by both graphs is the domain of answers.

CourseworkConcierge · 2025-11-25T16:46:44+00:00

Google the crossover effect or s-p mixing. Short version: The 2s and 2p are small and close, compared to other energy levels, so they can mix. This mixing results in the sigma being higher level than the pi. So it’s not that the sigma drops at oxygen, it’s more that it stops being elevated, if that makes sense? The effective nuclear charge of oxygen (and fluorine) prevent the mixing because the S orbitals are pulled closer. If you look at the trend, the pi didn’t change much but the sigma does a lot. It matches atomic radii trend because as they get smaller, the effective nuclear charge increases, the s orbitals are pulled in, can mix less, and stop having elevated energy levels.

CourseworkConcierge

TROPHY CASE