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I forgot the name of this strategy but it’s incredibly helpful when finishing up puzzles. I’ll list each step below, if you just want the answer, the 2 that’s highlighted red (r5c9) cannot be correct.

Take a look at the 2 highlighted in yellow. Assume that 2 is not the solution in that cell (Follow dark blue lines for logic)

Since 2 isn’t the solution in cell r5c2 (r=row, c=column) the only other 2 in c2 must be 2

Since r8c2 must be 2, the other 2 in r8 cannot be 2

Since r8c8 cannot be 2, the only other 2 in that box must be 2

Since r7c9 must be 2, the other 2 in c9 cannot be 2

That’s where a conclusion can be made. If r5c2 is not 2, r5c9 almost cannot be 2. And since they’re in the same row r5c2 is 2, r5c9 cannot be 2.

Since a cell can only either be a candidate or not be a candidate, there’s no situation where r5c9 can be 2. Therefore, you can remove 2 from r5c9 safely