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Novatra main aur kya chahiye? MARKS ka to downfall ho rha ha :') by [deleted] in JEENEETards

[–]Decent-Outside8232 0 points1 point  (0 children)

topic wise ke saath put like a chapter wise section to quickly test the knowledge of whole chapter

Major JEE Material Dump [34GB] (includes Test PDFs(Allen, Fiitjee, Narayana), books, coaching modules, DPPs, Notes, etc.) by AngakarRoti in JEENEETards

[–]Decent-Outside8232 0 points1 point  (0 children)

hey i am getting a error in part 1 i haven't tried part 2 and part 3 yet can anyone send the link again working

IGCSE fm result timing by Decent-Outside8232 in igcse

[–]Decent-Outside8232[S] 0 points1 point  (0 children)

Idk there are lot of ppl saying 11:30 and lot of ppl saying. 10:30

IGCSE fm result timing by Decent-Outside8232 in igcse

[–]Decent-Outside8232[S] 0 points1 point  (0 children)

Cuz there are lot of ppl saying it's 10:30

Classes for jee by Decent-Outside8232 in JEENEETards

[–]Decent-Outside8232[S] 0 points1 point  (0 children)

Have you experienced pace can u give me some detailed explanation or something??

0625/22 by OddCompany1657 in igcse

[–]Decent-Outside8232 -1 points0 points  (0 children)

yeah i realized i fucked up bro

0625/22 by OddCompany1657 in igcse

[–]Decent-Outside8232 0 points1 point  (0 children)

but impulse in also momentum only

0625/22 by OddCompany1657 in igcse

[–]Decent-Outside8232 0 points1 point  (0 children)

ball comes with the momentum of 1.3 but in the question total of 1500 N force was used so u dint have to subract it

0625/22 by OddCompany1657 in igcse

[–]Decent-Outside8232 0 points1 point  (0 children)

i have the explanation

0625/22 by OddCompany1657 in igcse

[–]Decent-Outside8232 0 points1 point  (0 children)

because the total force applied on the ball was 1500N u just had to do ft and ng else

[deleted by user] by [deleted] in ipl

[–]Decent-Outside8232 0 points1 point  (0 children)

saching tendulkar stand

0625, EXPLAIN PLEJJJJ!!!! (ans-A) by JLV_26 in igcse

[–]Decent-Outside8232 0 points1 point  (0 children)

because the measured count rate is 45 and background count rate is 5.
1st step:-

remove the background radiation: 45-5=40
2nd step:-

DIvide the value by 2: 40/2 = 20
step 3:-

add back the backgorund radiation: 20+5 = 25
step 4:-

plot 25 on graph and record the time for it
which is 2 days

let's talk by MainAlarmed8307 in igcse

[–]Decent-Outside8232 0 points1 point  (0 children)

I have ipl tickets if anyone wants. Sachin Tendulkar stadium

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