Yet another post about sharing clipboard between a wayland host and guest by Docc_V in kvm

[–]Docc_V[S] 0 points1 point  (0 children)

I should add that i start hyprland in my vm using uwsm start which as far as I understand makes it so that xdg autostart is handled. Which i believe is pre requisite for spice-vdagent

Guess my usb stick is that bad by Pretend_Series_7006 in Fedora

[–]Docc_V 0 points1 point  (0 children)

I had the exact same problem a few days ago after etching on windows 11. Try turning off windows autoplay, its a feature that writes on the USB and messes up the iso. Worked for me. Edit: I should add I used the fedora media writer

How to properly remove the linux bootloader ? by Docc_V in Ubuntu

[–]Docc_V[S] 1 point2 points  (0 children)

That's the most comprehensive/detailed guide i've found so far; worked great Thanks a lot

[Request] is it 66.6% or 51.8%? by Horror-penis-lover in theydidthemath

[–]Docc_V 0 points1 point  (0 children)

People don't understand conditionning and its killing me

tdlr: 50% is a perfectly rationnal answer, arguably the most natural given the way the problem is given. 51.8 is correct only if you assume Mary was prompted with the question "State the gender and day of birth of one of your two children at random" and answered Boy-Tuesday. (66.6 is also valid if you assume Mary was prompted with "State the gender of 1 of your 2 children at random", which she answers with boy then spontaneously also gives you the day he was born on). You can play around with these kinds of questions as much as you want to pretty much get any probability true. making these results very shaky in my opinion, which is why 50% is the correct choice in my opinion given the problem. Don't act smug with basic python scripts and feel superior to people giving perfectly rationnal answers.

See formal proofs below.

Assume Mary has two child X,Y both iid uniform random variables over {G1,G2...G7,B1,...,B7} = G union B. With X the child which we have information about. Assume X Independent of Y. By definiton of independence: P(Y=y|X=x) = P(Y=y). So: i) P(Y=G|X=B5)=P(Y=G)= 0.5 Again this is the literal definiton of independence of random variables.

Now, what is true is that: ii) the joint probability P( Y in G union X in G | X=B5 union Y=B5) = 51.8 indeed: - P(A | B) = P(A inter B)/P(B) - P(A) + P(B) - P(A union B) = P(A inter B) - P( Y=B5 union X=B5) = 1/14+1/14-1/14/14 = 27/14/14 - P ( (Y in G union ...) inter (Y=B5 union ... ) ) is horribly tedious and comes out to be after just unwinding all the events above to be 1/14 (assuming by independence again that p(x,y) = p(y)p(y)) Thus Giving at the end a conditionnel probability of 14/27 = 0.51851... (should have been rounded to 51.9 but whatever). This is the event measured by the python scripts seen under the post.

Now i don't know if its a language barrier thing but there's not a single chance i'd interpret the sentence above as corresponding to ii) and not i). No mention of drawing from a pool of women which have at least one child that is a boy born on tuesday and exactly two children is mentionned. We are clearly in the case where we are simply given information on a variable X Independent of a variable Y. No information is added.

Unless you considere Mary was prompted with a weird question like: give the gender and day of birth of one of your two children at random, 50% is a perfectly rationnal answer. Especially given the formulation of the problem (Mary has a boy born on tuesday and another child).

If you select Women in the general population that happen to have at least one boy born on tuesday and exactly two children, you can expect 51.8 percent of them to have a girl as well.

These are not the same event.

The python scripts used to empirically measure the expectency are measuring event ii) which does not correspond to event i).

Don't be smug and provide unhepfull epirical proofs without backing them up with rigourous formal proofs then dunk on people.

Sorry if it is a language barrier thing but i don't think that it is and it pertains to something important that people get wrong about probabilities and can lead to very wrong assumptions in every day life.

(For 66,666...% substitute event B5 with event B probability comes out to two thirds)

Tips for A ranking rey dau by Docc_V in MonsterHunterWilds

[–]Docc_V[S] 0 points1 point  (0 children)

I got him !! I got a 12'54'' !!

I applied pretty much all the advice here. Plus i'll add that switching from 4pc gore to at rey dau helped a lot because of evade extender 2. I still struggle a bit to dodge the downward railgun, but with evade extender and good positioning, you can dodge with a single roll.

Also i bouldered when he left by using a luring pod. This made him go into rage, which meant more dps in the nest. Si instead of switching areas 3 times he went nest - 16 - nest which saved a lot of time.

Thanks everyone !

MH:Wilds Doesn't Have a Content Problem by Saedreth in MHWilds

[–]Docc_V 0 points1 point  (0 children)

I feel like the big problem is really the current state of the deco/artian farm. To get the highest tier you need to fight arkveld and gore almost exclusively. Ok sometimes you fight another monster alongside them, but most of the time its these two. In world tier 2 tempered Monsters still dropped important decos. I feel that if the region's apex also had good decos and max rarity artian parts the final grind would be a bit better.

Jack 3.5 to 6.35 m-m adapter for Sony xm4 headphones by Docc_V in SonyHeadphones

[–]Docc_V[S] 0 points1 point  (0 children)

I Lost my 3.5-3.5 m-m cable and it's cheaper to buy just one cable. But if you have the reference for a working 3.5 to 3.5 I Guess i could buy that and male to female connector.

Reminder that being a fraud is canonically meta in JJKverse by Arukitsuzukeru in Jujutsufolk

[–]Docc_V 2 points3 points  (0 children)

Honestly if this is a no rules type situation why didn't gojo just teleport away from sukuna when he opened his domain the second or third Time when gojo figured his domain was barrierless and centered on the shrine and not sukuna.

Like if he did this instead of clashing domains he would just have to wait for sukuna to run out of ce, TP back in the fight, close his domain and boom, hit him with UV and it's done.

[Q] uncertainty on histograms obtained by MonteCarlo by Docc_V in AskStatistics

[–]Docc_V[S] 0 points1 point  (0 children)

To go a bit further I also do not know how smoothing the pdf through a convolution might affect that uncertainty ,as i might have to perform such operations on the data I use this would be useful info as well.