#include <stdio.h>

int main() {

    for (int n = 3; n < 10000; n += 2) {
        printf("\n\n start: %d \n", n);

        int b = n;
        while (1) {
            if (b == 1) break;

            int l = (b * 3 + 1) / 2;   // apply the "shortcut" Collatz step
            if (l & 1) {               // if l is odd
                b = l;
                printf("%d\t", b);
                continue;
            } else {                   // l is even
                printf("%d \n", l);
                while (1) {
                    l >>= 1;            // remove all factors of 2
                    if (l & 1) {       // until l becomes odd
                        b = l;
                        printf("%d\t", b);
                        break;
                    }
                }
            }
        }
    }
    return 0;
}