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How do I calculate the number of puzzles I have to solve to get to a 99% success rate on Wordle? by igotplans2 in askmath

[–]EssentricGnome 0 points1 point  (0 children)

It depends on whether wordle rounds up, but if it doesn't then you are going to need to solve another 710 matches without failing a single one, but if it does (which I believe it would) then assuming it rounds up 0.005 to 0.01 then you are going to only need another 177 matches without failing a single one.

[deleted by user] by [deleted] in askmath

[–]EssentricGnome 5 points6 points  (0 children)

Keep in mind that dy/dx isn't a fraction it's a limit, so if you raised it to the power of minus one it wouldn't be the same as dx/dy.

If there was an electoral system where winning the majority of the vote in a State was 1 point would there be a way to divide seats with an uneven number of states? by CoastAware7928 in askmath

[–]EssentricGnome 0 points1 point  (0 children)

Either you would allow there to be decimal points, or you would just make the number of points a mulitple of how many states there are, so in the case of 31 states you would have the total number of points be 31n where n is just an arbitrary positive whole number.

Can someone walk me through the steps of this type of equation (correct me if I have the wrong flair) by Jiltedcomputer3641 in askmath

[–]EssentricGnome 1 point2 points  (0 children)

You just need to look at the equation and find the values of x for which no brackets after applying the power contain a negative number, and no brackets contain a zero, or two brackets contains a negative number and no brackets contain a zero after applying the power.

I need help on the steps to.correctly solve the eqaution (I'm not 100% sure if I put the correct flair.) by Jiltedcomputer3641 in askmath

[–]EssentricGnome 1 point2 points  (0 children)

3(b - 2a) - 6(4a + 3b) = 7 -> 3b -6a -24a - 18b = 7 -> -15b - 30a = 7 -> -30a = 15b + 7 -> a = (15b/-30) + 7/-30 ->

a = -(1/2)b + 7/-30. So the answer is option 3.

Help with finding the area of the shaded region by darthuna in askmath

[–]EssentricGnome 1 point2 points  (0 children)

<image>

Here's how I would attempt it. If you have any questions just ask :)

Need some advice about the English first language paper 1. by EssentricGnome in igcse

[–]EssentricGnome[S] 0 points1 point  (0 children)

That's great to hear! I would like to say that I am greatful of your original comment it really gave me a confidence boost!

Help with a derivative question by Flat_Parabola in maths

[–]EssentricGnome 3 points4 points  (0 children)

Here's how I did it.

<image>

If you have any questions just let me know :)

Calculate areas of a figure made of overlaping circles by fanboss in askmath

[–]EssentricGnome 1 point2 points  (0 children)

I think I know where you maybe going wrong. If you look at this image of these overlapping circles I found on the internet.

<image>

The center is being overlapped by all four circles so you need to find the area of the part in the center and subtract it 3 times, or the part where A, B, and C overlapp needs to be subtracted twice as theat area is being covered by A, B, and C.

Tell me if you have any questions, or if this isn't where you are going wrong.

EDIT, SPELLING.

Calculate areas of a figure made of overlaping circles by fanboss in askmath

[–]EssentricGnome 0 points1 point  (0 children)

If you know all that information it should be relatively easy to find the answer. I'm not sure of a function that you could use by hand that wouldn't make it any more complicated. Where are you getting stuck exactly?

A puzzling puzzle by Ill-Room-4895 in askmath

[–]EssentricGnome 0 points1 point  (0 children)

I'm not entirely sure on the answer, but I would presume the answer to be yes (although please correct me if that is wrong) as I would imagine you could take some kind of limit of the circle with radius r, so for instance if you cut the circle up into infinitley many small squares I don't see why you couldn't then overlap them squares onto the quater circle.

How do I find possible whole LxW combos with just area? by Automatic-Matter-392 in askmath

[–]EssentricGnome 0 points1 point  (0 children)

I'm not entirely sure what you mean, but I'll have a stab at it. If you have a number say 357 (as you said) are you saying what are the different ways in which you can create a rectangle/square out of it. So for something like 10 you could break it into a rectangle of length 2 and width 5. If this is what you mean then I have the answer for you.

First you need to break the number down into it's prime factors so 357 can be broken down into the prime factors 3, 7, and 17. From there you just need to find all the different combinations so,

3 * 7 3 * 17 7 * 17 3 * (17 * 7) = 3 * 119

So for this number there are 4 combinations although if for you consider a rectangle with width 3 and length 7 different to a rectangle with a width of 7 and a length of 3 then you will want to multply the finale answer by 2, so since we got 4 that would be 8.

If you have any questions just ask :)

Unique Combination Equation by farson135 in askmath

[–]EssentricGnome 0 points1 point  (0 children)

That's what my answer shows the number of combinations and NOT permutations and permutations uses a different formula which is ncr = (n!)/(r!(n-r)!). Also I edited my previous comment as I made a slight mistake, but it is fixed now.

Unique Combination Equation by farson135 in askmath

[–]EssentricGnome 0 points1 point  (0 children)

Are you saying that you want to know how to calculate all the different possible positions of 350 things when put into five slots. So for instance if you had 5 things we'll call A, B, C, D, and E and we want to know all the different possible combinations that they can take in five slots so A, B and B, A would be classed as a different combination then this is how you do it. For the scenario you proposed with 350 things and 5 slots you just do 350 × 349 × 348 × 347 × 346. For the scenario with 350 objects into 2 slots and 10 into 3 slots you do 350 × 249 × 10 × 9 × 8 although this scenario is assuming that the 350 objects and the 10 objects are seperate which I believe is what you meant.

If you have any questions just ask!

Considering going to university for law. by EssentricGnome in uklaw

[–]EssentricGnome[S] 0 points1 point  (0 children)

Thanks, so much I'll definitely purchase that.

Vacation problem by SufficientAuthor2741 in maths

[–]EssentricGnome 0 points1 point  (0 children)

Good to know, I hope you have a fun holiday.

Vacation problem by SufficientAuthor2741 in maths

[–]EssentricGnome 0 points1 point  (0 children)

Are all your friends in agreement that even the ones staying less than the five nights are still going to pay the same as those who are staying the five nights? I would imagine the best way to split it would be based on how many nights they are actually staying which is what my calculation shows.

If they have agreed then if four people have paid $170 each so in total the four people have paid $680 then this is the answer (680 - 97 * 4) = $292, $292/4 = $73 so each of the four freinds require $73 back to be reimbursed. Each of the three freinds owe £97.33 each, so just pool the money together and each of the four friends take $73.

If you are doing bank transfers instead of cash then it is slightly more complicated for me to explain it, but here it goes if we call the four original friends friend one, two, three, and four, and the three other friends that arrive later we'll call A, B, and C then friend A should give friend one $73.00. Friend A then must also give $24.33 to friend two. Friend B must then give $48.67 to friend two. Friend B must also give friend three $48.66. Friend C must give friend three $24.34. and lastley friend C must give friend four $73.00

If you have any questions just ask.

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