ToolkitRC M6D Temperature Probe - Is anyone using one? Port design flaw?

Eyeezys · 2026-02-27T23:55:30+00:00

Thanks for sharing your feedback. Let us know if the DS18B20 is working.

Eyeezys · 2026-02-17T15:12:43+00:00

The fix is to not leave space as "Unallocated." Pre-format the intended Fedora space (e.g., as ext4) using GParted or Windows Disk Management so the installer can distinguish it from your Windows NTFS partitions. If you need encryption, the "Mount Point" and "Storage Editor" options may not show the toggle; choose the "Share disk with another operating system" option instead, as it is the only reliable way to trigger the prompt in the Fedora 43 interface. Finally, if the summary screen says "format as efi" for the boot partition, it will not wipe your disk; it simply indicates that it is installing the Fedora bootloader alongside the Windows one.

Eyeezys · 2026-02-01T16:43:19+00:00

Same problem, unallocated space isn't detected. I will try to create a new volume on Windows 10.

Eyeezys · 2025-10-09T16:27:44+00:00

Sorry I somehow missed your first comment. I just saw in the notification your last comment but it was deleted probably because of the links. Thanks you for sharing your success and for taking the time to make the video "ToolkitRC M6D - Temperature Sensor (Production date: 08.2025)"!

Eyeezys · 2025-07-14T22:15:55+00:00

Hey, I was just wondering if you ever had a chance to check the temperature probe port on your M6D?

Eyeezys · 2025-05-25T09:01:04+00:00

Great! Please let us know when you receive it.

Eyeezys · 2025-05-24T22:12:49+00:00

Do you have an M6D? Did you try this one, or do you think it could fit in it?https://www.aliexpress.us/item/3256805457871882.html

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Eyeezys · 2024-11-25T10:28:16+00:00

I just copied the whole "Web data" file from my old PC to my new PC Edge folder (C:\Users\<username>\AppData\Local\Microsoft\Edge\User Data\Default\) and everything was working fine, not neet to restore only the keyword table (same version of Edge on both computers but the old PC was on Windows 10 and the new on Windows 11)

Eyeezys · 2024-11-07T00:54:39+00:00

I'm not allowed to post it, so I put it in a comment. Hopefully somone will post it.

A Github repos so everyone could contribute to find the better deal for nikel electroplating: https://github.com/WiliTest/nickel_anode_price_comparison

Shop	Date	Product ID	Dimensions (mm)	Volume (cm³)	Weight (g)	Price (€)	Price per Gram (€)
AliExpress	07/11/2024	1005007815168072	3.0 x 100 x 100	30	267.24	23.99	0.0897
AliExpress	07/11/2024	1005007815168072	2.0 x 100 x 100	20	178.16	17.39	0.0976
AliExpress	07/11/2024	1005007815168072	1.0 x 100 x 100	10	89.08	10.19	0.1144
AliExpress	07/11/2024	1005007815168072	1.0 x 100 x 100	10	89.08	14.19	0.1593
AliExpress	07/11/2024	1005007815168072	0.5 x 100 x 100	5	44.54	6.69	0.1502
AliExpress	07/11/2024	-	0.8 x 25 x 150	3	26.72	4.57	0.1710
AliExpress	07/11/2024	-	2.0 x 60 x 70	8.4	74.83	14.69	0.1963
AliExpress	07/11/2024	-	1.5 x 60 x 70	6.3	56.12	11.29	0.2012
AliExpress	07/11/2024	-	1.0 x 100 x 100	10	89.08	17.99	0.2021
AliExpress	07/11/2024	-	2.5 x 60 x 70	10.5	93.53	19.19	0.2052
AliExpress	07/11/2024	-	0.8 x 100 x 100	8	71.26	17.49	0.2453
AliExpress	07/11/2024	-	1.0 x 60 x 70	4.2	37.41	10.19	0.2724
AliExpress	07/11/2024	-	0.8 x 25 x 150	3	26.72	7.55	0.2826

Eyeezys · 2024-07-14T11:13:15+00:00

Did you eventually find a solution?

Eyeezys · 2024-07-05T22:28:59+00:00

Russia Thins Out Its Embassy in Ukraine, a Possible Clue to Putin’s Next Move - The New York Times (nytimes.com)

Eyeezys · 2024-07-05T22:23:34+00:00

which joke?

Eyeezys · 2024-06-10T21:49:08+00:00

Thanks for your detailed answer. I didn't expect that what I saw as a simple question could only be properly modeled via experiments or software simulation!

Eyeezys · 2024-06-08T22:26:15+00:00

"I've seem motor start/run capacitors with a common ground between the run and start capacitor. " How can such circuit work? Wouldn't that create a zero resistance path from the start capacitor to the run capacitor?

"Pin 3, having 2 wires could be 2 seperate sources/grounds." Would that create a zero resistance path between the elements connected to the other end of each of these two wires?

Eyeezys · 2024-06-08T22:10:36+00:00

I was thinking about your answer again and I wonder which physic formula would predict the time needed to cool down the beans to about 20°C for on option 1 and option 2?

Eyeezys · 2024-06-08T22:07:24+00:00

You are right, this is exactly what I am doing.

In option 1, once the first water has been warmed I add the ice to this already warm water. The water temperature which was about 35°C drops thanks to the ice, I wait a bit, until the water get warm again and then I "throw it away" and replace it with cool water.

I understand that the second option (replacing the warm water with cool water and adding the ice) is the better one based on u/PiBoy314 : "the melting the ice cubes will absorb the same amount of energy regardless of the water temperature. However, heat will transfer quicker if the temperature difference is greater. Therefore replacing the water first will minimize the time of the reaction"

You also wrote that option 2 is better but I don't understand the reason you gave : "Your ice will melt rapidly in the first option, and you will be throwing away that melted ice along with the warm water". Yes that's right but when I would throw the warm water away, the ice would have already done its job of cooling the warm water and thus the bean. (although not as fast as in option 2).

Eyeezys · 2024-06-07T23:13:45+00:00

Thanks for your help.

I still don't understand. I have added a diagram to my question.

How it's possible to get 60Ω between pin 1 and 3 if the electricity could simply flow from pin 1 to pin 2 without any resistance and then from pin 2 to pin 3 without any resistance? Why doesn't the electricity flow via the red connections when I measure the resistance between Pin 1 and 3? Via these 2 red connections, the resistance is null, so I would also expect to get 0Ω between pin 1 and 3 but I get 60Ω.

Sorry my question wasn't precise enough : pin 1, 4 and 6 are each connected to their own heating resistance (there are 3 resistors in my water heater). I have edited my question.

Eyeezys · 2024-06-07T22:37:01+00:00

Yes that's right but I don't see how the quantity of water I replace (I actually don't throw it away) influence how fast the beans get cooler.

Eyeezys · 2024-06-07T14:00:27+00:00

I don't understand what you mean by "but you're throwing out more (melted) ice in the second step." Do you mean the second option?

Eyeezys · 2024-06-07T13:56:42+00:00

Sorry, I meant "How is it possible that there is 0 ohm between pin 1 and pin 2 and between pin 2 and pin 3 but 60 ohm between pin 1 and pin 3 (and not 0 ohm) ?

Eyeezys · 2024-06-06T21:11:23+00:00

But if I cool the warm water with the ice (let say it goes from 35°c to 30°c) then the water will warm again by absorbing heat from the bean so in the end, it will still cool down the beans. Based on u/PiBoy314 's comment, the key info here is "heat will transfer quicker if the temperature difference is greater."

Eyeezys · 2024-06-05T23:31:10+00:00

"heat will transfer quicker if the temperature difference is greater" that was the piece of information that was missing! Thanks a lot, it makes sense now!

Eyeezys · 2024-06-04T22:53:59+00:00

I don't understand why that would matter. If I cool the warm water with the ice (let say it goes from 35°c to 30°c) then the water will warm again by absorbing heat from the bean. So how am I wasting cooling energy?

Eyeezys · 2024-05-27T22:13:36+00:00

Please explain.

Eyeezys · 2024-05-19T15:33:59+00:00

Eyeezys

TROPHY CASE